Let the lengths of the sides of the rectangle be x and y. Then A(Area) = xy and 2(x+y)=300. You can use substitution to make one equation that gives A in terms of either x or y instead of both.
2(x+y) = 300
x+y = 150
y = 150-x
A=x(150-x) <--(substitution)
The resulting equation is a quadratic equation that is concave down, so it has an absolute maximum. The x value of this maximum is going to be halfway between the zeroes of the function. The zeroes of the function can be found by setting A equal to 0:
0=x(150-x)
x=0, 150
So halfway between the zeroes is 75. Plug this into the quadratic equation to find the maximum area.
A=75(150-75)
A=75*75
A=5625
So the maximum area that can be enclosed is 5625 square feet.
Answer:
25
Step-by-step explanation:
If (1/5)^2 equals 1/25, then (1/5)^-2 should be the opposite.
(1/5)^-2 equals 25
One pair of opposite sides both parallel and congruent implies a parallelogram.
Answer:
x=11°
Step-by-step explanation:
-Sum of angles of a triangle should alway be 180 degrees
35+110+2+3x=180
-Add all known values
147+3x=180
-Subtract 147 from both sides
3x=33
-Isolate x by divind both sides by 3
x=11°
<h3>9)</h3><h3>5 planes</h3>
<h3>10)</h3><h3>2 planes</h3>
<h3>11)</h3><h3>BCED</h3>
<h3>12)</h3><h3>Yes , they belong to plane (w)</h3>
