Answer:
its C. i hope this helps good luck and don't forget to thank and the brainly
Step-by-step explanation:
Step-by-step explanation:
A. When dealing with large numbers, sometimes it's easier to write them in a form of exponents of number ten. The value of the exponent shows how many times we multiply 10 by itself. That means that 10^3 is 10•10•10 or that 10^6 is 10•10•10•10•10•10.
So, when finding how many times on number is greater then the other, we need to divide them. We divide 8x10^6 by 2x10^5. It is done by dividing the numbers and subtracting the exponents; 8/2=4 and 10^6/10^5 is 10^6-5=10^1. So the correct answer is 4x10^1 which is 4x10, and that is 40.
B. Now, we have a total number of coins (2.25x10^5), and diametar of a coin (19mm = 19x10^-6km). Our task is to calculate the distance across which the coiks laid side-by-side would expand. We can find this by multiplying the number of coins with a diametar of single penny, 2.25x10^5•19x10^-6. Multiplying is done by multiplying the numbers (2.25x19=42.75) and adding the exponents (5+(-6)=5-6=-1). So, the distance is 42.75x10^-1km, which equals to 4.275 km. Obviously, this is less then the stated 5 km given in the text, so the reportet's statement is false.
Answer:
y - 8 = -2(x - 9)
Step-by-step explanation:
Given the slope, m = -2, and the point, (9, 8):
Let (x₁, y₁) = (9, 8)
slope (<em>m </em>) = -2
We can substitute these values into the following <u>point-slope form</u>:
y - y₁ = m(x - x₁)
y - 8 = -2(x - 9) ⇒ This is the point-slope form.
Answer:
d. 15
Step-by-step explanation:
Putting the values in the shift 2 function
X1 + X2 ≥ 15
where x1= 13, and x2=2
13+12≥ 15
15≥ 15
At least 15 workers must be assigned to the shift 2.
The LP model questions require that the constraints are satisfied.
The constraint for the shift 2 is that the number of workers must be equal or greater than 15
This can be solved using other constraint functions e.g
Putting X4= 0 in
X1 + X4 ≥ 12
gives
X1 ≥ 12
Now Putting the value X1 ≥ 12 in shift 2 constraint
X1 + X2 ≥ 15
12+ 2≥ 15
14 ≥ 15
this does not satisfy the condition so this is wrong.
Now from
X2 + X3 ≥ 16
Putting X3= 14
X2 + 14 ≥ 16
gives
X2 ≥ 2
Putting these in the shift 2
X1 + X2 ≥ 15
13+2 ≥ 15
15 ≥ 15
Which gives the same result as above.
The answer is <span>2.5 × 10⁻⁹ × 1.5 × 10³ = 3.75 × 10⁻⁶ </span>
