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antoniya [11.8K]
4 years ago
9

Small quantities of oxygen can be prepared in the laboratory by heating potassium chlorate, KClO3 ( is ) . The equation for the

reaction is 2 KClO3 ⟶ 2 KCl + 3 O 2 Calculate how many grams of O 2 ( g ) can be produced from heating 66.8 g KClO 3 ( s ) .
Chemistry
1 answer:
anyanavicka [17]4 years ago
4 0

Answer:

The answer to your question is  52.35 g of O₂

Explanation:

mass of oxygen = ?

mass of KClO₃ = 66.8 g

Chemical balanced reaction

              KClO₃   ⇒   2 KCl  +   3O₂

Process

1.- Calculate the molar mass of KClO₃ and Oxygen

KClO₃ = 39 + 35.5 + (16 x 3) = 122.5 g

O₂ = 16 x 6 = 96 g

2.- Write proportions to solve this problem

                     122.5 g of KClO₃ -----------------  96 g of O₂

                        66.8 g              -----------------  x

                        x = (66.8 x 96) / 122.5

                        x = 6412.8/122.5

                        x = 52.35 g of O₂

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