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3 years ago

What are the elements and number of atoms in the compound c6h12o6?

Chemistry

1 answer:

VARVARA [1.3K]3 years ago

3 0

<span>Carbon-6, Hydrogen-12, Oxygen-6
Number of atoms altogether: 24</span>

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Explain why the answer is correct and why the others aren’t. <br> Pleaseeee

Naya [18.7K]

Answer:

Buffalo and Watertown.

Explanation:

This is correct as the Interior lowlands are located ib the US. These are correct as the others are in the US but aren't located anywhere near the Interior Lowlands.

7 0

2 years ago

If the density of a 45.0 cm3 block of wood is 0.65 g/ml what is the mass of the wood?

wlad13 [49]

Answer:

$\boxed {\tt mass=29.25 \ grams}$

Explanation:

The density formula is mass over volume.

$d=\frac{m}{v}$

Rearrange the formula for the mass, m. Multiply both sides of the formula by v.

$d*v=\frac{m}{v}*v$

$d*v=m$

Mass can be found by multiplying the density and volume. The density is 0.65 grams per milliliter and the volume is 45.0 cubic centimeters.

A cubic centimeter is equal to a milliliter.

Therefore, 45 cubic centimeters also equals 45 milliliters.

$d= 0.65 \ g/mL\\v= 45 \ mL$

Substitute the values into the formula.

$0.65 \ g/mL * 45 \ mL=m$

Multiply. Note the milliliters, or mL will cancel out.

$0.65 \ g * 45=m$

$29.25 \ g=m$

The mass of the wood is 29.25 grams.

5 0

3 years ago

He partial lewis structure that follows is for a hydrocarbon molecule. in the full lewis structure, each carbon atom satisfies t

Bezzdna [24]

Answer:

Four (4) hydrogen atoms

Explanation:

C=C-C(triple bond)C

only four hydrogen atoms can bond with the vacant space

6 0

3 years ago

Read 2 more answers

CaCO3(s) ⇄ CaO(s) + CO2(g) 0.100 mol of CaCO3 and 0.100 mol CaO are placed in an 10.0 L evacuated container and heated to 385 K.

Montano1993 [528]

Answer:

The final mass of CaCO3 is 10.68 grams

Explanation:

Step 1: Data given

Number of moles CaCO3 = 0.100 moles

Number of moles CaO = 0.100 moles

Volume = 10.0 L

When equilibrium is reached the pressure of CO2 is 0.220 atm. 0.250 atm of CO2 is added, while keeping the temperature constant

Step 2: The balanced equation

CaCO3(s) <==> CaO(s) + CO2(g)

Step 3: Calculate moles of CO2

n = PV/RT

⇒n = the initial number of moles CO2 = TO BE DETERMINED

⇒P = the pressure of CO2 at theequilibrium = 0.220 atm

⇒V = the volume of the container = 7.0 L

⇒R = the gas constant = 0.08206 L*atm / mol * K

⇒T = the temperature = 385 K

n = 0.220*7.0/(0.08206*385) = 0.0487 (mol)

this is the amount of CaCO3 which has been converted to CaO before pumping-in additional 0.225 atm CO2(g).

Step 4: Calculate moles CaCO3

After adding additional 0.250 atm CO2(g), the equilibrium CO2 pressure is still 0.220 atm. All this additional CO2 would completely convert to CaCO3:

n = PV/RT = 0.250*7.0/(0.08206*385) = 0.0554 moles

The total CaCO3 after equilibrium is reestablished is:

0.100 - 0.0487+ 0.0554 = 0.1067 mol

Step 5: Calculate mass CaCO3

Mass CaCO3 = 0.1067 moles * 100.09 g/mol

Mass CaCO3 = 10.68 grams

The final mass of CaCO3 is 10.68 grams

8 0

3 years ago

Match the following .....

prohojiy [21]

Answer:Rocket is lauched for first one, Second one is the wagon one and third one is seabelt impact.

Explanation:

5 0

2 years ago

Read 2 more answers