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bulgar [2K]
3 years ago
11

What is an advantage of using an electromagnet rather than a regular magnet?

Physics
2 answers:
Naddik [55]3 years ago
7 0
<h3><u>Answer;</u></h3>

<em>The advantage of using electromagnet over a regular magnet is that </em><u><em>the magnetic field or the strength of the magnet can be quickly adjusted by controlling the amount of electric current in the coil.</em></u>

<h3><u>Explanation;</u></h3>
  • <em><u>Electromagnets are made by winding a wire through a magnetic material such as soft iron core making a coil, and then passing electric current through the coil thus making the soft iron core magnetic. </u></em>
  • <u><em>The strength of the electromagnet depends on the number of coils and also the size of the electric current through the coil.</em></u>
  • Permanent magnets on the other hand do not require power but depends on the type of material used to make it.
  • Therefore,<em><u> its advantageous to use electromagnets as compared to using permanent magnets since the strength of the electromagnet can be easily adjusted by regulating the amount of current flowing through the coils.</u></em> Thus, the electromagnet can be adjusted for have different levels of magnetic fields.
alexdok [17]3 years ago
5 0
<span>The advantage of using an electromagnet rather than a regular magnet is that an electromagnet is stronger and you can control the power of the magnet. </span>
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A particle of mass 6.3 x 10-8kg and charge 7.1 muC is traveling due east. It enters perpendicularly a magnetic field whose magni
ASHA 777 [7]

Answer:

t=0.016s

Explanation:

we can use

\frac{v}{r}=\omega=\frac{qB}{m}=\frac{7.1*10^{-6}C*1.7T}{6.3*10^{-8}kg}=191.58s^{-1}

the time that the particle is in the magnetic field is one half oa period. Hence

t=\frac{T}{2}=\frac{\pi}{\omega}=0.016s

I hope this is useful for you

regards

8 0
3 years ago
How can you verify the archimedes principle?​
Ipatiy [6.2K]

Answer:

It is found that W1 - W2 loss in weight of solid when immersed in water is equal to the weight of the water displaced by the body. This verifies Archimedes' principle.

6 0
3 years ago
Tom’s father is 48 years old. He is not able to see nearby objects clearly. (ref: p.508-511)
marin [14]

Answer:

Explanation:

a.) hypermetropia is the reason for his problem

b.)Image is formed farther from the near point

c.) defect is corrected by convex lens

7 0
4 years ago
Read 2 more answers
A compressor receives air at 290 K, 100 kPa and a shaft work of 5.5 kW from a gasoline engine. It is to deliver a mass flow rate
Sladkaya [172]

Answer:

P_2=4091\ KPa

Explanation:

Given that

T₁ = 290 K

P₁ = 100 KPa

Power P =5.5 KW

mass flow rate

\dot{m}= 0.01\ kg/s

Lets take the exit temperature = T₂

We know that

P=\dot{m}\ C_p (T_2-T_1)

5.5=0.01\times 1.005(T_2-290})\\T_2=\dfrac{5.5}{0.01\times 1.005}+290\ K\\\\T_2=837.26\ K

If we assume that process inside the compressor is adiabatic then we can say that

\dfrac{T_2}{T_1}=\left(\dfrac{P_2}{P_1}\right)^{0.285}

\dfrac{837.26}{290}=\left(\dfrac{P_2}{100}\right)^{0.285}\\2.88=\left(\dfrac{P_2}{100}\right)^{0.285}\\

2.88^{\frac{1}{0.285}}=\dfrac{P_2}{100}

P_2=40.91\times 100 \ KPa

P_2=4091\ KPa

That is why the exit pressure will be 4091 KPa.

4 0
3 years ago
A .5kg football is thrown with a velocity of 15m/s to the right. A stationary receiver catch the bail and bring it to rest in 0.
storchak [24]
<h3>Answer:</h3>

375 N

<h3>Explanation:</h3>

Topic tested: Newton's Law of motion

The question is testing on the application of Newton's second Law of motion.

We are given;

  • Mass of the football = 5 Kg
  • Initial velocity of the football, Vf = 15 m/s
  • Time taken to bring the ball to rest = 0.2 s
  • Final velocity, Vo = 0 m/s ( since the ball went to rest)

We are required to determine the force exerted to bring it to rest.

  • According to the Newton's second law of motion the resultant force and rate of change in momentum are directly proportion.
  • Therefore;

F=\frac{(MVf-MVo)}{t}

Thus;

F=\frac{(5kg.5m/s)-(5kg.0m/s)}{0.2s}

F=375Newtons

Force = 375 N

Hence, the force exerted on the ball by the receiver was 375 N

5 0
4 years ago
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