Ask question

Ask question

All categories

3 years ago

5

3.60×10^23 nitrogen molecules collide with a 16.0 cm^2 wall each second. Assume that the molecules all travel with a speed of 45

0 m/s and strike the wall head on. What is the pressure on the wall?

1 answer:

Oksi-84 [34.3K]3 years ago

8 0

Answer:

The pressure on the wall is 9416.25 N/m²

Explanation:

Please see the attachments below

You might be interested in

Two blocks are connected by a massless rope that passes over a 1 kg pulley with a radius of 12 cm. The rope moves over the pulle

tangare [24]

Answer:

$F=1.159$

Explanation:

From the question we are told that:

Mass of pulley $M=1kg$

Radius $r=12cm$

Mass of block A $M_a=2.1kg$

Mass of block B $m_b=4.1kg$

Spring constant $\mu= 358 J/m2$

Generally the equation for Torque is mathematically given by

Since $\sumF=ma$

At mass A

$T_2-f_3=2.1a$

At mass B

$4.8-T_1=4.1a$

At Pulley

$R(T_1-T_2)=\frac{1*1*R^2}{2}\frac{a}{R}$

$R(T_1-T_2)=0.55a$

Therefore the equation for total force F

At mass A+At mass B+At Pulley

$(T_2-f_3+4.8-T_1+R(T_1-T_2)=2.1a+4.1a+0.55a$

$(T_2-f_3+4.8-T_1+R(T_1-T_2)=2.7a+4.8a+0.55a$

$-f_3+4.1=6.75a$

$-f_3=6.75a+4.8$

Since From above equation

$M_{eff}=6.7kg$

Therefore

$T=2\pi \sqrt{{\frac{M_{eff}}{k}}$

$T=2\pi \sqrt{{\frac{6.75}{\mu}}$

$T=0.862s$

Generally the equation for frequency is mathematically given by

$F=\frac{1}{T} \\F=\frac{1}{0.862}$

$F=1.159$

3 0

3 years ago

After driving a portion of the route, the taptap is fully loaded with a total of 25 people including the driver, with an average

loris [4]

Answer:

0.4455 m

Explanation:

g = Acceleration due to gravity = 9.81 m/s²

Total mass is

$m=62\times 25+15\times 3+5\times 3+25\\\Rightarrow m=1635\ kg$

Here the spring constant is not given so let us assume it as $k=36000\ N/m$

Here, the forces are balanced

$mg=kx\\\Rightarrow 1635\times 9.81=36000\times x\\\Rightarrow x=\dfrac{1635\times 9.81}{36000}\\\Rightarrow x=0.4455\ m$

The springs are compressed by 0.4455 m

3 0

4 years ago

The use of a simple machine will reduce the amount of work needed to move an object.true false

Eddi Din [679]

False they simple machines do not reduce the amount of work you do it would just reduce the amount of force you use.

3 0

3 years ago

A 55.0-kg box rests on a horizontal surface. The coefficient of static friction between the box and the surface is 0.300. What h

MariettaO [177]

Answer:

161.86 N

Explanation:

mass of box m= 55.0 kg

weight of the box, mg= 55×9.81

g here is acceleration due to gravity =9.81 m/sec^2

coefficient of friction between the box and the surface μ= 0.3

the friction force F_s= μmg= 0.3×55×9.81

=161.86 N

to move the ball horizontal force required is 161.86 N

8 0

3 years ago

Two particles, one with charge -6.29 × 10^-6 C and one with charge 5.23 × 10^-6 C, are 0.0359 meters apart. What is the magnitud

navik [9.2K]

Answer:

Force, F = −229.72 N

Explanation:

Given that,

First charge particle, $q_1=-6.29\times 10^{-6}\ C$

Second charged particle, $q_2=5.23\times 10^{-6}\ C$

Distance between charges, d = 0.0359 m

The electric force between the two charged particles is given by :

$F=k\dfrac{q_1q_2}{d^2}$

$F=9\times 10^9\times \dfrac{-6.29\times 10^{-6}\times 5.23\times 10^{-6}}{(0.0359)^2}$

F = −229.72 N

So, the magnitude of force that one particle exerts on the other is 229.72 N. Hence, this is the required solution.

4 0

3 years ago