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SCORPION-xisa [38]
3 years ago
6

A .5kg football is thrown with a velocity of 15m/s to the right. A stationary receiver catch the bail and bring it to rest in 0.

2s. what is the force exerted on the bail by the receiver?
Physics
1 answer:
storchak [24]3 years ago
5 0
<h3>Answer:</h3>

375 N

<h3>Explanation:</h3>

Topic tested: Newton's Law of motion

The question is testing on the application of Newton's second Law of motion.

We are given;

  • Mass of the football = 5 Kg
  • Initial velocity of the football, Vf = 15 m/s
  • Time taken to bring the ball to rest = 0.2 s
  • Final velocity, Vo = 0 m/s ( since the ball went to rest)

We are required to determine the force exerted to bring it to rest.

  • According to the Newton's second law of motion the resultant force and rate of change in momentum are directly proportion.
  • Therefore;

F=\frac{(MVf-MVo)}{t}

Thus;

F=\frac{(5kg.5m/s)-(5kg.0m/s)}{0.2s}

F=375Newtons

Force = 375 N

Hence, the force exerted on the ball by the receiver was 375 N

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Explanation:

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