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soldi70 [24.7K]
3 years ago
9

What is f(0) when f(x)=3-2

Mathematics
1 answer:
anyanavicka [17]3 years ago
8 0

Answer:

f(0)=-2

Step-by-step explanation:

We are given that f(x)=3x-2

And we are asked to determine f(0)

In order to do so, we will replace x with 0 in our function

Hence

f(0) = 3(0)-2

f(0)=0-2

f(0)=-2

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3x + 8 = -x + 20 What is x?
g100num [7]
First, lets take all the x values on one side.

3x + x + 8 = -x + x + 20
4x + 8 = 20

Now, lets put the numbers on the other side.

4x + 8 - 8 = 20 - 8
4x = 12
x = 3

Hope this helps!
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5 0
3 years ago
Read 2 more answers
If f(x)=3x^2+1 and g(x) =1-x, what is the truly value of (f-g)(2)
Lilit [14]

Answer:

14

Step-by-step explanation:

f(x)=3x²+1

f(2) = 3 x 2² + 1 = 13

g(x) =1-x

g(2) = 1 - 2 = -1

(f-g)(2) f(2) - g(2) = 13 - (-1) = 14

8 0
3 years ago
240,000 written as a whole number multiplied by the power of ten
Stolb23 [73]
This question can be also asked as what is the scientific notation of the number 240,000. The scientific notation is written as <span>a whole number multiplied by the power of ten. It should be written as follows:

2.4 x 10^5

Hope this helps. Have a nice day.</span>
8 0
3 years ago
Find the quotient of these Complex Numbers. <br><br><br> (5-i) / (3+2i)
JulsSmile [24]

Let the given complex number

z = x + ix = \dfrac{5-i}{3+2i}

We have to find the standard form of complex number.

Solution:

∴ x + iy = \dfrac{5-i}{3+2i}

Rationalising numerator part of complex number, we get

x + iy = \dfrac{5-i}{3+2i}\times \dfrac{3-2i}{3-2i}

⇒ x + iy = \dfrac{(5-i)(3-2i)}{3^2-(2i)^2}

Using the algebraic identity:

(a + b)(a - b) = a^{2} - b^{2}

⇒ x + iy = \dfrac{15-10i-3i+2i^2}{9-4i^2}

⇒ x + iy = \dfrac{15-13i+2(-1)}{9-4(-1)} [ ∵ i^{2} =-1]

⇒ x + iy = \dfrac{15-2-13i}{9+4}

⇒ x + iy = \dfrac{13-13i}{13}

⇒ x + iy = \dfrac{13(1-i)}{13}

⇒ x + iy = 1 - i

Thus, the given complex number in standard form as "1 - i".

5 0
3 years ago
I really need help with this, my teacher doesn't really teach and I'm stumped again.​
yarga [219]

Answer:

JMK = 54

JKH = 126

HLK = 90

HJL = 27

LHK = 63

JLK = 27

Step-by-step explanation:

Just use 180 for total angles in each triangle. Vertical angles mean the opposite to 126 is 126 and the other two that make up the inner vertices are (360- 126*2)/2 = 54

So, 126, `16, 54 , 54 are the inner angles in the circle. Just go from there.

5 0
2 years ago
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