For with equation would you add 12 as the first step in the solution?<br>

Factor completely 4u^2-28u+49

icang [17]

$\bold{Answer}$

$\boxed{\bold{\left(2u-7\right)^2}}$

$\bold{Explanation}$

$\bold{Factor: \ 4u^2-28u+49}$

$\bold{---------------------}$

$\bold{Rewrite \ 4u^2-28u+49: \ \left(2u\right)^2-2\cdot \:2u\cdot \:7+7^2}$

$\bold{\left(2u\right)^2-2\cdot \:2u\cdot \:7+7^2}$

$\bold{Apply \ Perfect \ Square \ Formula \ \left(a-b\right)^2=a^2-2ab+b^2: \ a=2u,\:b=7}$

$\bold{\left(2u-7\right)^2}$

$\boxed{\bold{Eclipsed}}$

3 0

3 years ago

Read 2 more answers

Paul used 3/4cup of butter in a batch of brownies. He ate 1/6 of the batch of brownies. What fraction of a cup of butter did he

Ronch [10]

The answer is 1/8 cups. you have to take 1/6 of 3/4.

8 0

3 years ago

Find the exact value of sin (-270 degrees).

user100 [1]

The exact value of sin (-270) is determined using the calculator in degrees mode. The answer is equal to 1. If the radians mode is used, -270 is equal to -2 pi/3. Hence using the calculator, we can verify that the answer is still 1. The value of -270 matters.

3 0

3 years ago

GETS BRAINILIST!!!!The table shows the relationship between the number of drops of food color added to different number of cups

Kryger [21]

Answer:

I would say the first one

Step-by-step explanation:

A graph is shown. The title of the graph is Cake Decorating. The horizontal axis label is Frosting in cups. The horizontal axis values are 0, 10, 20, 30, 40, 50, 60. The vertical axis label is Food Color in drops. The vertical axis values are 0, 20, 40, 60, 80, 100, 120.

8 0

4 years ago

How many different combinations are possible if each lock contains the numbers 0 to 39, and each combination contains three dist

Georgia [21]

(e) Each license has the formABcxyz;whereC6=A; Bandx; y; zare pair-wise distinct. There are 26-2=24 possibilities forcand 10;9 and 8 possibilitiesfor each digitx; yandz;respectively, so that there are 241098 dierentlicense plates satisfying the condition of the question.3:A combination lock requires three selections of numbers, each from 1 through39:Suppose that lock is constructed in such a way that no number can be usedtwice in a row, but the same number may occur both rst and third. How manydierent combinations are possible?Solution.We can choose a combination of the formabcwherea; b; carepair-wise distinct and we get 393837 = 54834 combinations or we can choosea combination of typeabawherea6=b:There are 3938 = 1482 combinations.As two types give two disjoint sets of combinations, by addition principle, thenumber of combinations is 54834 + 1482 = 56316:4:(a) How many integers from 1 to 100;000 contain the digit 6 exactly once?(b) How many integers from 1 to 100;000 contain the digit 6 at least once?(a) How many integers from 1 to 100;000 contain two or more occurrencesof the digit 6?Solutions.(a) We identify the integers from 1 through to 100;000 by astring of length 5:(100,000 is the only string of length 6 but it does not contain6:) Also not that the rst digit could be zero but all of the digit cannot be zeroat the same time. As 6 appear exactly once, one of the following cases hold:a= 6 andb; c; d; e6= 6 and so there are 194possibilities.b= 6 anda; c; d; e6= 6;there are 194possibilities. And so on.There are 5 such possibilities and hence there are 594= 32805 such integers.(b) LetU=f1;2;;100;000g:LetAUbe the integers that DO NOTcontain 6:Every number inShas the formabcdeor 100000;where each digitcan take any value in the setf0;1;2;3;4;5;7;8;9gbut all of the digits cannot bezero since 00000 is not allowed. SojAj= 9<span>5</span>

8 0

3 years ago

For with equation would you add 12 as the first step in the solution?​

For with equation would you add 12 as the first step in the solution?