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sesenic [268]
2 years ago
15

The period of time during which an IDPS monitors network traffic to observe what constitutes normal network behavior is referred

to as ______.
Computers and Technology
1 answer:
horrorfan [7]2 years ago
5 0

Answer: Training period

Explanation:

The training period is refers to the period of time where we can monitor all the network traffic and also observe all the networking behavior with the constitute.

  • During the training period we get a proper training about the specific topic and also get a chance to learn various types of things.

 According to the given question, in the training period an IDPS monitor is used observing the networking traffic and the network behavior. Therefore, raining period is the correct answer.

 Therefore, Training period is the correct answer.

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One way to protect against a security threat to a computer system is to __________. Avoid external links with inconsistent URLs
Makovka662 [10]

One way to protect against a security threat to a computer system is to Avoid external links with inconsistent URLs.

<h3>What is malware?</h3>

Malware is any programme that is purposely designed to disrupt a computer, server, client, or computer network, leak private information, obtain unauthorised access to information or systems, deny users access to information, or otherwise interfere with the user's computer security and privacy.

One way to protect against a security threat to a computer system is to Avoid external links with inconsistent URLs. The reason for this is that such links may contain malware or spyware.

Learn more about Malware:

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7 0
2 years ago
For a new version of processor, suppose the capacitive load remains, how much more energy will the processor consume if we incre
erastovalidia [21]

Answer:

The answer is below

Explanation:

The amount of power dissipated by a processor is given by the formula:

P = fCV²

Where f = clock rate, C = capacitance and V = Voltage

For the old version of processor with a clock rate of f, capacitance C and voltage of V, the power dissipated is:

P(old) = fCV²

For the new version of processor with a clock rate of 20% increase = (100% + 20%)f = 1.2f, capacitance is the same = C and voltage of 20% increase = 1.2V, the power dissipated is:

P(new) = 1.2f × C × (1.2V)² = 1.2f × C × 1.44V² =1.728fCV² = 1.728 × Power dissipated by old processor

Hence, the new processor is 1.728 times (72.8% more) the power of the old processor

4 0
2 years ago
Major findings of evolution of computers
Elis [28]

Answer:

twitt

Explanation:

3 0
3 years ago
Please pass this on... ( #helpsavelives )
olya-2409 [2.1K]

Answer:

Thank you

Explanation:

That made my day. I will make sure to pass it on.

4 0
3 years ago
Jason needs to design the colors for a web site that make it easy to read. Which should he consider using?
Umnica [9.8K]

Answer:

a. Contrasting background and text

Explanation:

3 0
3 years ago
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