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Elza [17]
3 years ago
14

Explain how it is possible for a sequence of packets transmitted through a wide area network to arrive at their destination in a

n order that differs from that in which they were sent. Why can’t this happen in a local network?)
Computers and Technology
1 answer:
dalvyx [7]3 years ago
5 0

Answer:

- Different route paths, due to dynamic routing in WAN.

- Local area networks have one or very few paths to destination and does not require dynamic routing.

Explanation:

A wide area network is a network that covers a large geographical area. It goes beyond the private local area network, with more routing paths and network intermediate devices. The router is an essential tool for routing packets between devices. It requires a routing path, learnt statically or dynamically to work.

There are mainly two types of route paths, they are, static routes and dynamic routes.

The dynamic routes are used mainly in WAN. Sometimes, there can be multiple path to a destination, the router determines the best path to send the packets. It sends the sequenced packets through all available path and they arrive at the destination depending on the path used, the packets arrive in an out -of-order fashion in the destination and a rearranged.

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you're troubleshooting an ip addressing issue, and you issue a command to view the system's tcp/ip configuration. the command yo
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Based on the above, the operating systems the person is  working on is known to be called Linux.

<h3>What is Linux used for?</h3>

Linux is known to be a kind of an open-source Unix-like operating system that is known to be focused on the Linux kernel, which is said to be a kind of an operating system kernel that was said to have been first released on September 17, 1991.

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Therefore, Based on the the given description above, the operating systems the person is  working on is known to be called Linux.

Learn more about Linux from

brainly.com/question/12853667
#SPJ1

You are troubleshooting an IP addressing issue, and so issue a command to view the TCP/IP configuration of the system. The command you use produces the following output:

fxp0: flags=8843&lt;UP, BROADCAST, RUNNING, SIMPLEX, MULTICAST&gt; mtu 1500

inet6 fe80: :2a0:83ff:fe30:57a%fxp0 prefixlen 64 scopeid 0x1

inet 192.168.1.235 netmask 0xfffffx00 broadcast 255.255.255..255

ether 00:a0:83:30:05:7a

media: Ethernet autoselect (100BaseTX &lt;full-duplex&gt;)

status: active

1o0: flags=8049&lt;UP, LOOPBACK, RUNNING, MULTICAST&gt; mtu 16384

inet6 : : 1prefixlen 128

inet6 fe90: : 1%1o0 prefixlen 64 scopeid 0x7

inet 127.0.0.1 netmask 0xff000000

Which of the following operating systems are you working on?

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