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const2013 [10]
4 years ago
11

What is the approximate circumference of a circle with a radius of 40 inches? Use π ≈ 3.14.

Mathematics
1 answer:
Vlada [557]4 years ago
6 0
To find cirfumfrence we use the formula C = 2 \pi r
Soooo
\pi = 3.14
r = 40 inches
So now we plug it in :P
C = 2 x 3.14 x 40 = 251.2 
answer = B.) 251.2 inches 
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164

Step-by-step explanation:

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Ramona had 8 3/8 in. of ribbon. She used 2 1/2 in. for an art project.How many inches of ribbon does she have left?
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8\frac{3}{8}= \frac{67}{8}

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2.According to www.city-data, the mean price for a detached house in Franklin County, OH in 2009 was $192,723. Suppose we know t
igor_vitrenko [27]

Answer:

0.7123 = 71.23% probability that a random sample of 75 detached houses in Franklin County had a mean price greater than $190,000 in 2009.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The mean price for a detached house in Franklin County, OH in 2009 was $192,723. Suppose we know that the standard deviation was $42,000.

This means that \mu = 192723, \sigma = 42000

Sample of 75:

This means that n = 75, s = \frac{42000}{\sqrt{75}}

What is the probability that a random sample of 75 detached houses in Franklin County had a mean price greater than $190,000 in 2009?

1 subtracted by the p-value of Z when X = 190000. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{190000 - 192723}{\frac{42000}{\sqrt{75}}}

Z = -0.56

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1 - 0.2877 = 0.7123

0.7123 = 71.23% probability that a random sample of 75 detached houses in Franklin County had a mean price greater than $190,000 in 2009.

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3 years ago
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