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Goshia [24]
3 years ago
14

Your friend called and told you that he saw information about the classified XYZ program on the Internet. As a cleared employee

who does not work on the XYZ program, is it okay for you to view that information on the Internet since it's already in the public domain?
Computers and Technology
1 answer:
mamaluj [8]3 years ago
8 0

Answer:

Yes

Explanation:

Based on this scenario it can be said that Yes, it is ok for you to view this information. The main reason for this being that the information is already in the public domain. Even though you are cleared you still do not have the authority to view private information from the companies projects because you do no longer work for the company but since it has been leaked and already viewed by the entire world then it is ok for you to view as well. Anything made public on the internet can be viewed by anyone around the world.

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Match the vocabulary to the appropriate definition.
Allisa [31]

Answer:

Pulling related code together in objects is Arrays

Helps programmers when they revisit code or are new to code-- Documentation

Explanation:

This is all I know

3 0
2 years ago
Most network cards contain a port that accepts a(n) ____, which looks similar to a telephone connector but is larger.
Vadim26 [7]
YOUR ANSWER IS -------- It accepts a RJ-45 connector
hope i helped you :).
take care
8 0
3 years ago
One interesting application of computers is to display graphs and bar charts. Write an application that reads five numbers betwe
Nezavi [6.7K]

Answer:

The answer to this question can be given by program that  are as follows

import java.util.*;

//import package for taking input from user.

public class Main   //define class

{

public static void main (String ag[] )   //define main function

{

 int number;

 Scanner input = new Scanner(System.in);

 for (int i = 0; i < 5; i ++)                       //loo for input.

 {

  System.out.print ("Enter a number between 1 - 30:  ");

  number = input.nextInt();          //input number by the user.

 

 }

 asterisk();           //calling function.

 }

public static void asterisk()          //defination of function.

{

    //body of function.

    int n;                   //local variable.

 for (n= 0; n <= 30; n++)                  //using loop for print asterisk

 {

 if (n !=0)

 //printf used for print value.

 System.out.printf("*", n );                  //print value.

 }

 

  for (n= 0; n <= 30; n++)         //using loop for print asterisk

  {

 if (n !=0)

 //printf used for print value.

 System.out.printf("*", n );     //print value.

 }

 

  for (n= 0; n <= 30; n++)          //using loop for print asterisk

  {

 if (n !=0)

 //printf used for print value.

 System.out.printf("*", n );          //print value.

 }

  for (n= 0; n <= 30; n++)            //using loop for print asterisk

 

 {

 if (n !=0)

 //printf used for print value.

 System.out.printf("*", n );               //print value.

 }

 

  for (n= 0; n <= 30; n++)             //using loop for print asterisk

  {

 if (n !=0)

 //printf used for print value.

 System.out.printf("*", n );             //print value.

 }

}

}

Output:

Enter a number between 1 - 30: 2

Enter a number between 1 - 30: 2

Enter a number between 1 - 30: 1  

Enter a number between 1 - 30: 3

Enter a number between 1 - 30: 4

*******************************************************************************

Explanation:

In this program we take 5 time input from the user and print the value in the form of (*) that can be explain in above output section.In that program we use printf method that is also used for print the value.

3 0
3 years ago
A Function checkMe takes three parameters, a character and two integers. If the sum of the two integers is negative, and the cha
Paul [167]

Answer:

Check the explanation

Explanation:

Here is the program with function definition and two sample calls.

Code:

#include <iostream>

using namespace std;

//checkMe FUNCTION which takes values a, b and c

void checkMe(char &a, int &b, int &c)

{

//if sum of b and c is negative and a is 'n', b and c are set to 0, otherwise a is set to 'p'

if((b+c)<0 && a=='n')

{

b = 0;

c = 0;

}

else

{

a = 'p';

}

}

int main()

{

//first test case when else part is executed

char a = 'n';

int b = 5;

int c = 6;

 

checkMe(a, b, c);

 

cout<<a<<" "<<b<<" "<<c<<endl;

 

//second test case when if part is executed

a = 'n';

b = -4;

c = -5;

 

checkMe(a, b, c);

 

cout<<a<<" "<<b<<" "<<c<<endl;

return 0;

}

Kindly check the Output below:

7 0
3 years ago
Angelina has added page numbers to her report, but all of the pages are labeled "Page 1" at the bottom. What caused
notka56 [123]

Answer:(A)

<em><u>Why?</u></em>

A footer is an area at the bottom of a document page that contains data common to other pages.

6 0
3 years ago
Read 2 more answers
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