A student performed the following steps to find the solution to the equation x^2 +14x +40 = 0. Where did the student go wrong? S

Question

madreJ [45]

3 years ago

10

A student performed the following steps to find the solution to the equation x^2 +14x +40 = 0. Where did the student go wrong? S

tep 1. Factor the polynomial into (x + 4) and (x + 10) Step 2. x + 4 = 0 and x + 10 = 0 Step 3. x = -4 and x = 10

Mathematics

1 answer:

klio [65] · Answer 1 · 2022-09-11T03:41:13+03:00

The student went wrong in Step 3.

After setting each factor equal to 0, the student solved for x wrong in the second equation. To solve for x in the second equation, the student should subtract 10 from both sides. The solutions of the equation would be X = -4 and X = -10.

X + 10 = 0
X + 10 -<em>10 </em>= 0 <em>- 10</em>
X = -10