Two consecutive even integers have the following property. When the smaller integer is added to three times the larger integer,
the result is two less than five times the smaller integer. Find the two consecutive even integers
1 answer:
let x be the first integer
x+ 2 the second integer ( two consecutive even )
smaller integer added to three times the larger <span>x + 3 ( x+2)
</span>two less than five times the smaller <span>5x - 2</span>
x + 3 ( x+2) = 5x - 2
x+3x +6 = 5x -2
x=8
the first integer = 8
the second is x+2 =10
You might be interested in
Answer:
16 divided by 2 equals C which is 8.
Step-by-step explanation:
Answer: 6:18
All of the other options are equal to 1:3
The distance between any two points is:
d^2=(x2-x1)^2+(y2-y1)^2
d^2=(6--2)^2+(4--4)^2
d^2=8^2+8^2
d^2=64+64
d^2=128
d=√128 units
Answer:135
Step-by-step explanation:
bcs 45x60 is 2700 ÷20= 135
I think its C but not sure