Let's multiply the first equation by 3. (As you can see y's coefficient in the first one is 1 and in the second one is -3 , we will multiply the first equation by 3 so when we add the equations their sum will be 0)
Now let's add this new equation and our second equation.
We found x=-3
Now let's plug x's value in one of the equations to find y's value.
So we found y=5
Solution ;
(-3, 5)
Answer:
Slope =y2−y1x2−x10−3105−12−31092−310⋅1092⋅10−345−115
Step-by-step explanation:
Slope =y2−y1x2−x10−3105−12−31092−310⋅1092⋅10−345−115
answer is option A
becoz solution set is x < -10 where -5 > -10 so -5 is not in solution set
Try this solution (based on 3 steps: equation of the line; points in this line; equation of the plane).
This is the theory of algebra, to simply the expression we proceed as follows;
[sqrt(x-2)+5/sqrt(x-2)]/(x-2)
simplifying the numerator we get:
sqrt(x-2)+5/sqrt(x-2)
=[x-2+5]/sqrt(x-2)
=(x+3)/sqrt(x-2)
therefore our entire expression will be:
[(x+3)/sqrt(x-2)]/(x-2)
[(x+3)/(x-2)^(1/2)]*1/(x-2)
applying the law if indices we get
=(x+3)/(x-2)^(3/2)
