If the slope is 0, then x does not change at all.
take the given y coordinate, and make that the equation.
so y=-9, since the line will never change.
Answer: 23, 25, 27
Step-by-step explanation:
Let the 3 consecutive odd numbers be x, x+2 and x+4.
So
2x+(x+2)+3(x+4)=152
2x + x + 2 + 3x + 12 = 152
6x+14=152
6x = 152 - 14
x=138/6
x=23
So, the numbers are 23, 25 and 27.
The equation of a circle in standard form is
![(x - h)^2 + (y - k)^2 = r^2](https://tex.z-dn.net/?f=%20%28x%20-%20h%29%5E2%20%2B%20%28y%20-%20k%29%5E2%20%3D%20r%5E2%20)
where (h, k) is the center of the circle, and r is the radius if the circle.
We need to find the radius and center of the circle.
We are given a diameter, so to find the center, we need the midpoint of the diameter.
M = ((-6 + 6)/2, (6 + (-2))/2) = (0, 2)
The center is (0, 2).
To find the radius, we find the length of the given diameter and divided by 2.
![d = \sqrt{(-6 - 6)^2 + (6 - (-2))^2)}](https://tex.z-dn.net/?f=%20d%20%3D%20%5Csqrt%7B%28-6%20-%206%29%5E2%20%2B%20%286%20-%20%28-2%29%29%5E2%29%7D%20)
![d = \sqrt{144 + 64}](https://tex.z-dn.net/?f=%20d%20%3D%20%5Csqrt%7B144%20%2B%2064%7D%20)
![d = \sqrt{208}](https://tex.z-dn.net/?f=%20d%20%3D%20%5Csqrt%7B208%7D%20)
![r = \dfrac{d}{2} = \dfrac{\sqrt{208}}{2} = \dfrac{\sqrt{208}}{\sqrt{4}} = \sqrt{52}](https://tex.z-dn.net/?f=%20r%20%3D%20%5Cdfrac%7Bd%7D%7B2%7D%20%3D%20%5Cdfrac%7B%5Csqrt%7B208%7D%7D%7B2%7D%20%3D%20%5Cdfrac%7B%5Csqrt%7B208%7D%7D%7B%5Csqrt%7B4%7D%7D%20%3D%20%5Csqrt%7B52%7D%20)
![(x - 0)^2 + (y - 2)^2 = (\sqrt{52})^2](https://tex.z-dn.net/?f=%20%28x%20-%200%29%5E2%20%2B%20%28y%20-%202%29%5E2%20%3D%20%28%5Csqrt%7B52%7D%29%5E2%20)
Answer:
Step-by-step explanation: