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Leviafan [203]
3 years ago
14

What molecules both enters AND exits the Kreb's cycle?

Biology
1 answer:
kykrilka [37]3 years ago
4 0
<span>Pyruvic acid enters and<span> carbon dioxide exits but the only one that is there is pyruvic acid so its pyruvic acid.</span>

</span>
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1
kiruha [24]

Answer:

Thermal and radiant

Explanation:

Thermal energy is energy in the form of heat (such as fire). Light energy is a form of radiant energy. When a match is struck it creates fire which creates heat (thermal energy) and light (radiant energy) so the two types of energy that the match is transformed into are thermal and radiant.

7 0
2 years ago
did Anna appear to be following a diet appropriate for a person with type 1 diabetes and why or why not
Sphinxa [80]
While you didn't provide us with a list of foods that Anna is eating or has eaten in the past, her diet would be appropriate for her if she was abstaining from food that has a high glycemic impact (bread, pasta, candy, chocolate) on her body, or just food which contains glucose in general. Both of these are not allowed for diabetics as they might trigger unwanted effects. 
5 0
3 years ago
In addition to Earth, which planet has evidence of water on the surface?
Free_Kalibri [48]

answer:

mars

explanation:

  • this is why scientists expect to find life on mars or even for humans to live there
6 0
3 years ago
4. The Rh blood type response system is controlled by the D allele. The genotypes DD and Dd are Rh (Rh positive); dd is Rh- (Rh
DedPeter [7]

Answer:

A - Frequency of D allele = 0.35

Frequency of d allele = 0.65

B- Frequency of DD genotype = 0.1225

Frequency of Dd genotype = 0.455

Frequency of dd genotype = 0.425.

C - Total population = 400

Frequency of heterozygous population = 400*0.455 = 183.

EXPLANATION:

The equilibrium sum of all the allelic frequency of a gene is always 1 and sum of all the genotypic frequency of all the genotype is always 1 - This is according to Hardy-Weinberg.

So p+q =1

p2+ 2pq+q2 =1

where p = frequency of dominant allele

q is the frequency of the recessive allele.

from the question, it was given that there were  170 individual out of 400, which were Rh- negative,

So q2 = 170/400 = 0.425

q= 0.65

Also p+q =1

so p = 1-q

or p = 1-0.65

Hence p =0.35

Frequency of homozgupus for D allele = 0.35*0.35 = 0.1225

Frequency of heterozygous or Dd will be 2pq.

or 2*0.35*0.65 = 0.455

A - Frequency of D allele = 0.35

Frequency of d allele = 0.65

B- Frequency of DD genotype = 0.1225

Frequency of Dd genotype = 0.455

Frequency of dd genotype = 0.425.

C - Total population = 400

Frequency of heterozygous population = 400*0.455 = 183.

8 0
3 years ago
Read 2 more answers
I need the answer to all please
Bond [772]

Answer:

ok

Explanation:

5 0
3 years ago
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