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Gennadij [26K]
3 years ago
11

Which of the following shapes is most similar to Earth’s orbit?

Biology
1 answer:
ivanzaharov [21]3 years ago
3 0

Answer:

Ellipse

Explanation:

Earth's orbit (and the orbit of other planetary bodies) are not perfect circles - they are in fact elliptical.

According to Kepler's first law, all planets travel around the Sun with an elliptical orbit, with the Sun being a focus of the ellipse.

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Identify an example of vestigial structure
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Answer:

Examples of vestigial structures include the human appendix, the pelvic bone of a snake, and the wings of flightless birds. Vestigial structures can become detrimental, but in most cases these structures are harmless; however, these structures, like any other structure, require extra energy and are at risk for disease.

Explanation:

sincerely, micah

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The 6-kingdom system of classification divides the former kingdom Monera into two kingdoms, Eubacteria and
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Explanation:

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Archaebacteria

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2 years ago
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RasD oncogenes directly activate Cdc42 and Rac, which in turn, activate Rho. Which cancer hallmark does this contribute to:_____
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I think it would be B
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3 years ago
The researchers also found that after 150 days, the relative change in virulence of B. thuringiensis was greater than the relati
Debora [2.8K]

Answer:  pathogen–host coevolution

Explanation:

A major driver of evolution is Reciprocal coevolution between host and pathogen. Rather than pathogen, one-sided adaptation to a nonchanging host, high virulence specifically favoured during pathogen–host coevolution. In all of the independent replicate populations under coevolution, the pathogen ( B. thuringiensis ) genotype BT-679 with known nematocidal toxin genes of C. elegans and high virulence specifically swept to fixation but only some of them go under one-sided adaptation,

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7 0
3 years ago
Albinism in humans is caused by homozygosity for mutant recessive alleles of the tyr gene, which is located on chromosome 11. al
yanalaym [24]
Exactly 989527/1048576, or approximately 94.37%  
Since each trait is carried on a different chromosome, the two traits are independent of each other. Since both parents are heterozygous for the trait, each parent can contribute 1 of a possible 4 combinations of the alleles. So there are 16 possible offspring. I'll use "a", "A", "b", "B" to represent each allele and the possible children are aabb, aabB, aaBb, aaBB, aAbb, aAbB, aABb, aABB, Aabb, AabB, AaBb, AaBB, AAbb, AAbB, AABb, and AABB 
Of the above 16 possibilities, there are 7 that are homozygous in an undesired traint and 9 that don't exhibit the undesired trait. So let's first calculate the probability of "what are the chances that all 5 children not exhibiting an undesired trait?" and then subtract that result from 1. So 
1-(9/16)^5 = 1 - 59049/1048576 = 989527/1048576 which is approximately 0.943686485 = 94.3686485%  
So the answer is exactly 989527/1048576, or approximately 94.37%
8 0
3 years ago
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