By the quadratic formula, the <em>solution</em> set of the <em>quadratic</em> equation is formed by two <em>real</em> roots: x₁ = 0 and x₂ = - 12.
<h3>How to find the solution of quadratic equation</h3>
Herein we have a <em>quadratic</em> equation of the form a · m² + b · m + c = 0, whose solution set can be determined by the <em>quadratic</em> formula:
x = - [b / (2 · a)] ± [1 / (2 · a)] · √(b² - 4 · a · c) (1)
If we know that a = - 1, b = 12 and c = 0, then the solution set of the quadratic equation is:
x = - [12 / [2 · (- 1)]] ± [1 / [2 · (- 1)]] · √[12² - 4 · (- 1) · 0]
x = - 6 ± (1 / 2) · 12
x = - 6 ± 6
Then, by the quadratic formula, the <em>solution</em> set of the <em>quadratic</em> equation is formed by two <em>real</em> roots: x₁ = 0 and x₂ = - 12.
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Answer:
The slope of the two points is 2. (8/4)
Answer:
.66
Step-by-step explanation:
Answer:
Final answer is c=-7.
Step-by-step explanation:
Given equation is
.
Now question says that Misha wrote the quadratic equation 0=-x2+4x-7 in standard form. Now we need to find about what is the value of c in her equation.
We know that standard form of quadratic equation is given by
.
compare given equation with the standard form, we find that -7 is written in place of +c
so that means +c=-7
or c=-7
Hence final answer is c=-7.