Given: Triangle JKL is dilated from the origin at a scale factor of 10 to create triangle J′K′L′.
Required: Correct option that complete the statement.
Explanation:
Now, triangle is dilated from the origin at a scale factor of 10.
So, the sides will become larger, but angles will remain the same.
Hence, the triangles will be similar as sides will be in proption (SSS rule).
So, The triangles are similar because their corresponding sides are proptional and their corresponding angles are congurent.
Final Answer: Second group is correct answer.
Answer:the cost of one day lily = $9 and cost of one pot of ivy = $2
Step-by-step explanation:
Step 1
let day lilies be rep as d
and ivy be represented as i
So that The expression for what Willie spent on 12 day lilies and 4 pots of ivy = $116 be
12 d+ 4i = 116 ---- equation 1
and for Anjali spending $60 on 6 day lilies and 3 pots of ivy be
6d+ 3i = $60------ equation 2
Step 2 --- Solving
12 d+ 4i = 116 ---- equation 1
6d+ 3i = $60------ equation 2
Multiply equation 2 by (2) and subtracting equation 1 from it
12d+ 6i= 120
--12 d+ 4i = 116
2 i= 4
i = 4/2 = 2
TO find d, putting the value of i = 2 in equation 1 and solving
12d+ 4(2) = 116
12d= 116-8
12d= 108
d= 108/12= 9
Therefore the cost of one day lily = $9 and cost of one pot of ivy = $2
2^3 = 2 x 2 x 2 = 8
your answer is 8
hope this helps
Answer:
Step-by-step explanation:
Begin by squaring both sides to get rid of the radical. Doing that gives you:
Now use the Pythagorean identity that says
and make the replacement:
. Now move everything over to one side of the equals sign and set it equal to 0 so you can factor:
and then simplify to
Factor out the common cos(x) to get
and there you have your 2 trig equations:
cos(x) = 0 and 1 - cos(x) = 0
The first one is easy enough to solve. Look on the unit circle and see where, one time around, where the cos of an angle is equal to 0. That occurs at
The second equation simplifies to
cos(x) = 1
Again, look to the unit circle and find where the cos of an angle is equal to 1. That occurs at π only.
So, in the end, your 3 solutions are
