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4 years ago

4cos(10x)+2=2 What would this equal in Degrees??

Mathematics

1 answer:

Ipatiy [6.2K]4 years ago

7 0

Answer:

Simplifying

4cos(10x) + 2 = 2

Remove parenthesis around (10x)

4cos * 10x + 2 = 2

Reorder the terms for easier multiplication:

4 * 10cos * x + 2 = 2

Multiply 4 * 10

40cos * x + 2 = 2

Multiply cos * x

40cosx + 2 = 2

Reorder the terms:

2 + 40cosx = 2

Add '-2' to each side of the equation.

2 + -2 + 40cosx = 2 + -2

Combine like terms: 2 + -2 = 0

0 + 40cosx = 2 + -2

40cosx = 2 + -2

Combine like terms: 2 + -2 = 0

40cosx = 0

Solving

40cosx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Divide each side by '40'.

cosx = 0.0

Simplifying

cosx = 0.0

The solution to this equation could not be determined.

Step-by-step explanation:

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3 years ago

( g(1) = 14<br> (g(n) = g(n − 1) – 4<br> Find an explicit formula for g(n).<br> g(n) =

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Answer:

$g(n)=18-4n$

Step-by-step explanation:

You are given the function g, for which

$g(1)=14,\\\\g(n)=g(n-1)-4$

Find some values of this function:

$g(1)=14\\ \\g(2)=g(2-1)-4=g(1)-4=14-4=10\\ \\g(3)=g(3-1)-4=g(2)-4=10-4=6\\ \\g(4)=g(4-1)-4=g(3)-4=6-4=2\\ \\...$

You can see that ecah next value is 4 less than previous one, so these values form an arithmetic sequence and you have to find the nth term of this sequence. The nth term of arithmetic sequence is

$a_n=a_1+(n-1)d,$

where

$a_1=g(1)=14\\ \\d=-4$

So,

$g(n)=a_n=14+(n-1)\cdot (-4)=14-4n+4=18-4n$

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3 years ago