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3 years ago

Help me Solve for X (round to the nearest hundreth)

Mathematics

1 answer:

mario62 [17]3 years ago

7 0

The answer is: <span>16.82
it's tan (angle)=opposite/adjacent</span>

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A landscaping company is laying a triangular flower bed. The height of the trangle is 15ft. What lengths of the base will make t

mash [69]

Answer:

28 ft

Step-by-step explanation:

The height of the triangle = 15 ft

The least required area A = 210 ft^2

We know that the area of a triangle = 1/2bh

Where

b is the base

h is the height

Substituting, we have

210 = 1/2 x b x 15

210 = 15/2 x b

420/15 = b

b = 28 ft

5 0

3 years ago

one half hour past midnight. write the time using a.m or pm. and one half hour after 4:00 in the morning

Darina [25.2K]

The correct answer is 12:30am and 4:30 am

8 0

3 years ago

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Find the number c that satisfies the conclusion of the Mean Value Theorem on the given interval. (Enter your answers as a comma-

Ostrovityanka [42]

Answer:

2.25

Step-by-step explanation:

The computation of the number c that satisfied is shown below:

Given that

$f(x) = \sqrt{x}$

Interval = (0,9)

According to the Rolle's mean value theorem,

If f(x) is continuous in {a,b) and it is distinct also

And, f(a) ≠ f(b) so its existance should be at least one value

i.e

$f^i(c) = \frac{f(b) - f(a)}{b -a }$

After this,

$f(x) = \sqrt{x} \\\\ f^i(x) = \frac{1}{2}x ^{\frac{1}{2} - 1} \\\\ = \frac{1}{2}x ^{\frac{-1}{2}$

$f^i(x) = \frac{1}{{2}\sqrt{x} } = f^i(c) = \frac{1}{{2}\sqrt{c} } \\\\\a = 0, f (a) = f(o) = \sqrt{0} = 0 \\\\\ b = 9 , f (b) = f(a) = \sqrt{9} = 3\\$

After this,

Put the values of a and b to the above equation

$f^i(c) = \frac{f(b) - f(a)}{b - a} \\\\ \frac{1}{{2}\sqrt{c} } = \frac{3 -0}{9-0} \\\\ \frac{1}{\sqrt[2]{c} } = \frac{3}{9} \\\\ \frac{1}{\sqrt[2]{c} } = \frac{1}{3} \\\\ \sqrt[2]{c} = 3\\\\\sqrt{c} = \frac{3}{2} \\\\ c = \frac{9}{4}$

= 2.25

4 0

3 years ago

The top two nets represent the triangular prisms that are attached to the bases of a rectangular prism. The composite figure is

hodyreva [135]

Answer:

282 square units

Step-by-step explanation:

I just answered this question

7 0

4 years ago

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❗️❗️❗️Find the length of side x in simplest radical form with a rational denominator.❗️❗️❗️

tiny-mole [99]

Answer:

$x=\frac{\sqrt{14} }{2}$

Step-by-step explanation:

Notice that you are given an isosceles right-angle triangle to solve, since each of its two acute angles measures $45^o$ . Then such means that the sides opposite to these acute angles (the so called "legs" of this right angle triangle) must also be of the same length (x).

We can then use the Pythagorean theorem that relates the square of the hypotenuse to the addition of the squares of the triangles legs:

$(\sqrt{7})^2=x^2+x^2\\7=2\,x^2\\x^2=\frac{7}{2} \\x=+/-\sqrt{\frac{7}{2}} \\x=+/-\frac{\sqrt{14} }{2}$

We use just the positive root, since we are looking for an actual length. then, the requested side is:

$x=\frac{\sqrt{14} }{2}$

6 0

3 years ago