All categories

3 years ago

Reflect the point (7,0) across the y-axis

Mathematics

2 answers:

Nezavi [6.7K]3 years ago

4 0

Answer:

(- 7, 0)

Step-by-step explanation:

Under a reflection in the y- axis

a point (x, y ) → (- x, y )

Hence

(7, 0 ) → (- 7, 0 )

stiks02 [169]3 years ago

3 0

$A(7,0)\Longrightarrow\boxed{A'(-7,0)}$

Hope this helps.

r3t40

You might be interested in

I need help with that

Digiron [165]

9514 1404 393

Answer:

AC ≈ 7.3

Step-by-step explanation:

Corresponding sides of similar triangles are proportional.

AC/BC = DF/EF

AC/18 = 15/37 . . . . fill in the given values

AC = 18(15/37) . . . multiply by 18

AC ≈ 7.3

4 0

3 years ago

Please help fast.

podryga [215]

$\huge{\underline{\boxed{\tt{Answer:}}}}$

Let AB be a chord of the given circle with centre and radius 13 cm.

Then, OA = 13 cm and ab = 10 cm

From O, draw OL⊥ AB

We know that the perpendicular from the centre of a circle to a chord bisects the chord.

∴ AL = ½AB = (½ × 10)cm = 5 cm

From the right △OLA, we have

OA² = OL² + AL²

==> OL² = OA² – AL²

==> [(13)² – (5)²] cm² = 144cm²

==> OL = √144cm = 12 cm

Hence, the distance of the chord from the centre is 12 cm.

━═━═━═━═━═━═━═━═━━═━═━═━═━═━

8 0

3 years ago

Acellus

Step2247 [10]

Answer:

57 cm²

Step-by-step explanation:

Surface area of the yellow prism = front + back + right + left + top

✔️Area of the front = L * W

L = 4 cm

W = 3 cm

Area of the front = 4*3 = 12 cm²

✔️Area of the back = L * W

L = 4 cm

W = 3 cm

Area of the back = 4*3 = 12 cm²

✔️Area of the right face = L * W

L = 4 cm

W = 3 cm

Area of the right face = 4*3 = 12 cm²

✔️Area of the left face = L * W

L = 4 cm

W = 3 cm

Area of the left face = 4*3 = 12 cm²

✔️Area of the top = L * W

L = 3 cm

W = 3 cm

Area of the top = 3*3 = 9 cm²

✅Total = 12 + 12 + 12 + 12 + 9 = 57 cm²

4 0

3 years ago

dale has a square garden. He adds a 2-foot-wide walkway around his garden. If the total area of the walkway and garden is 196 sq

dem82 [27]

Let the side of the garden alone (without walkway) be x.
Then the area of the garden alone is x^2.
The walkway is made up as follows:

1) four rectangles of width 2 feet and length x, and
2) four squares, each of area 2^2 square feet.

The total walkway area is thus x^2 + 4(2^2) + 4(x*2).

We want to find the dimensions of the garden. To do this, we need to find the value of x.

Let's sum up the garden dimensions and the walkway dimensions:

x^2 + 4(2^2) + 4(x*2) = 196 sq ft

x^2 + 16 + 8x = 196 sq ft

x^2 + 8x - 180 = 0

(x-10(x+18) = 0

x=10 or x=-18. We must discard x=-18, since the side length can't be negative. We are left with x = 10 feet.

The garden dimensions are (10 feet)^2, or 100 square feet.

4 0

3 years ago

A store has been selling 300 Blu-ray disc players a week at $600 each. A market survey indicates that for each $40 rebate offere

timurjin [86]

Answer:

75 $

Step-by-step explanation:

According to problem statement p(300) = 600

And we know that with a rebate of 40 $, numbers of units sold will increase by 80 then if x is number of units sold, the increase in units is

( x - 300 ) , and the price decrease

(1/80)*40 = 0,5

Then the demand function is:

D(x) = 600 - 0,5* ( x - 300 ) (1)

And revenue function is:

R(x) = x * (D(x) ⇒ R(x) = x* [ 600 - 0,5* ( x - 300 )]

R(x) = 600*x - 0,5*x * ( x - 300 )

R(x) = 600*x - 0,5*x² - 150*x

R(x) = 450*x - (1/2)*x²

Now taking derivatives on both sides of the equation we get

R´(x) = 450 - x

R´(x) = 0 ⇒ 450 - x = 0

x = 450 units

We can observe that for 0 < x < 450 R(x) > 0 then R(x) has a maximum for x = 450

Plugging this value in demand equation, we get the rebate for maximize revenue

D(450) = 600 - 0,5* ( x - 300 )

D(450) = 600 - 225 + 150

D(450) =

D(450) = 600 - 0,5*( 150)

D(450) = 600 - 75

D(450) = 525

And the rebate must be

600 - 525 = 75 $

5 0

3 years ago