Grayson: 35h + 35 = y
Ian: 45h + 15 = y
(Substituting first hour in h)
35h + 35 = y
35(1) + 35
y = 70$ in the first hour for Grayson
45h + 15 = y
45(1) + 15
y = 60$ in the first hour for Ian
Grayson charges > Ian charges
(Substituting second hour in h)
35h + 35 = h
35(2) + 35
105$ in the second hour for Grayson
45h + 15 = h
45(2) + 15
135$ in the second hour for Ian
Grayson charges < Ian charges
Answer:
In the first hour Grayson charges more than Ian.
Answer:
Step-by-step explanation:
Research decreases satisfaction
Answer:
x=8,−2
Step-by-step explanation:
First, you move all the terms to one side
x^2−6x+9−25=0
Then you simplify
x^2 −6x−16=0
Factor
(x−8)(x+2)=0
Which will result in x=8,−2
we need to find 1% of 10000 first
so we divide 10000:100= 100 (that's 1%)
to find the 60% which will be accepted we multiply 100 × 60 = 6000 students accepted
of those 6000 we need to find 50% which is ½ so we basically just divide by 2, aka 6000 : 2 = 3000 people which will be enrolled
Answer:
0
Step-by-step explanation:
g(x) = x^2 - x - 2
Substitute x = 2:
g(2) = 4 - 2 - 2 = 0
