Answer:
Step-by-step explanation:
Hi there!
Slope-intercept form: 
where <em>m</em> is the slope and <em>b</em> is the y-intercept (the value of y when x=0)
<u>1) Determine the slope (</u><u><em>m</em></u><u>)</u>
where two points that fall on the line are 
and 
On the graph, two points are highlighted for us: (0,-4) and (2,2). Plug these into the formula:
Therefore, the slope of the line is 3. Plug this into :
<u>2) Determine the y-intercept (</u><u><em>b</em></u><u>)</u>
Recall that the y-intercept occurs when x=0. Given the point (0,-4), the y-intercept is therefore -4. Plug this into :
I hope this helps!
Answer:
Minimum 8 at x=0, Maximum value: 24 at x=4
Step-by-step explanation:
Retrieving data from the original question:
![f(x)=x^{2}+8\:over\:[-1,4]](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E%7B2%7D%2B8%5C%3Aover%5C%3A%5B-1%2C4%5D)
1) Calculating the first derivative
2) Now, let's work to find the critical points
Set this
0, belongs to the interval. Plug it in the original function
3) Making a table x, f(x) then compare
x| f(x)
-1 | f(-1)=9
0 | f(0)=8 Minimum
4 | f(4)=24 Maximum
4) The absolute maximum value is 24 at x=4 and the absolute minimum value is 8 at x=0.
Answer: In 5 years it will be worth £455
Step-by-step explanation:
Step 1
Given
The cost of the T.V. for Colin = £530.
The rate of depreciation per year = 3%
Time/ period = 5 years
Formulae to be used
F = P X (1 - r) ^ n
where
F = the future value after depreciation
P = the present value.
r =the interest rate per time period
n = the time/ periods
Step 2--- SOLVING
F = P X (1- r) ^ n
F= 530 x (1-0.03) ^ 5
=530 x 0.858734
=£455.129
Rounding up to the nearest penny where appropriate = £455
The first letter can be any one of 26 letters. For each one . . .
The second letter can be any one of 26 letters. For each one . . .
The first digit can be any one of 10 digits. For each one . . .
The second digit can be any one of 10 digits. For each one . . .
The third digit can be any one of 10 digits. For each one . . .
The fourth digit can be any one of 10 digits. For each one . . .
The fifth digit can be any one of 10 digits.
The total number of possibilities is
(26 x 26 x 10 x 10 x 10 x 10 x 10) =
( 26² x 10⁵) = (676 x 100,000) = <em>67,600,000</em> .
let each box length be 1
<em><u>for</u></em><em><u> </u></em><em><u>white</u></em><em><u> </u></em><em><u>triangle</u></em>
area = ½bh
=½(4)(2)
=4
<em><u>f</u></em><em><u>o</u></em><em><u>r</u></em><em><u> </u></em><em><u>o</u></em><em><u>r</u></em><em><u>a</u></em><em><u>n</u></em><em><u>g</u></em><em><u>e</u></em><em><u> </u></em><em><u>t</u></em><em><u>r</u></em><em><u>i</u></em><em><u>a</u></em><em><u>n</u></em><em><u>g</u></em><em><u>l</u></em><em><u>e</u></em>
area=½(2)(3)
=3
<em><u>f</u></em><em><u>o</u></em><em><u>r</u></em><em><u> </u></em><em><u>b</u></em><em><u>l</u></em><em><u>u</u></em><em><u>e</u></em><em><u> </u></em><em><u>m</u></em><em><u>a</u></em><em><u>r</u></em><em><u>k</u></em><em><u>e</u></em><em><u>d</u></em><em><u> </u></em><em><u>b</u></em><em><u>o</u></em><em><u>x</u></em><em><u>e</u></em><em><u>s</u></em>
each of the box
area=l²
=(1)²
=1
there are 16 boxes
so the total area will be 16
total area of the hexagon = 4+3+16
=23 square units
