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3 years ago

Put these numbers in order 55, 52, 46, 52, 46, 43, 49, 56, 42

Mathematics

2 answers:

Sphinxa [80]3 years ago

5 0

Answer: 55

Step-by-step explanation:

Studentka2010 [4]3 years ago

3 0

Answer:

42,43,46,46,49,52,52,55,56

Step-by-step explanation:

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Parallelogram RSTU is rotated 180° clockwise

julia-pushkina [17]

Answer:

Two pairs of parallel sides

Step-by-step explanation:

The given transformation performed on parallelogram RSTU = 180° clockwise rotation

Given that a rotation is a form of rigid transformation, the shape and size of the preimage RSTU will be equal to the the shape and size of the image R'S'T'U'

Therefore, RSTU ≅ R'S'T'U' and R'S'T'U' is also a parallelogram with two pairs of parallel sides.

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3 years ago

I need help with math

Mila [183]

1. x = 16
2. x = 46

Good luck

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3 years ago

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Subtract. (4x + 7) - (x+1) A. 3x + 8 B. 3x + 6 C. 4x + 8 O D. 4x + 6 Lmk

Studentka2010 [4]

Answer:

4x + 7 - ( x + 1)

Remove the bracket

We get

4x + 7 - x - 1

= 3x + 6

That's option B

Hope this helps.

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3 years ago

Read 2 more answers

What should I buy? A study conducted by a research group in a recent year reported that of cell phone owners used their phones i

Llana [10]

Answer:

The probability that seven or more of them used their phones for guidance on purchasing decisions is 0.7886.

Step-by-step explanation:

The question is incomplete:

What should I buy? A study conducted by a research group in a recent year reported that 57% of cell phone owners used their phones inside a store for guidance on purchasing decisions. A sample of 14 cell phone owners is studied. Round the answers to at least four decimal places. What is the probability that seven or more of them used their phones for guidance on purchasing decisions?

We can model this as a binomial random variable, with p=0.57 and n=14.

$P(x=k)=\dbinom{n}{k} p^{k}q^{n-k}$

a) We have to calculate the probability that seven or more of them used their phones for guidance on purchasing decisions:

$P(x\geq7)=\sum_{k=7}^{14}P(x=k)\\\\\\$

$P(x=7)=\dbinom{14}{7} p^{7}q^{7}=3432*0.0195*0.0027=0.1824\\\\\\P(x=8) = \dbinom{14}{8} p^{8}q^{6}=3003*0.0111*0.0063=0.2115\\\\\\P(x=9) = \dbinom{14}{9} p^{9}q^{5}=2002*0.0064*0.0147=0.1869\\\\\\P(x=10) = \dbinom{14}{10} p^{10}q^{4}=1001*0.0036*0.0342=0.1239\\\\\\P(x=11) = \dbinom{14}{11} p^{11}q^{3}=364*0.0021*0.0795=0.0597\\\\\\P(x=12) = \dbinom{14}{12} p^{12}q^{2}=91*0.0012*0.1849=0.0198\\\\\\P(x=13) = \dbinom{14}{13} p^{13}q^{1}=14*0.0007*0.43=0.004\\\\\\$