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aleksklad [387]
3 years ago
15

Put these numbers in order 55, 52, 46, 52, 46, 43, 49, 56, 42

Mathematics
2 answers:
Sphinxa [80]3 years ago
5 0

Answer: 55

Step-by-step explanation:

Studentka2010 [4]3 years ago
3 0

Answer:

42,43,46,46,49,52,52,55,56

Step-by-step explanation:

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6 pages every 1/5 hour in unit rates
Alecsey [184]

Answer:

30 <em>pages per hour</em>

Step-by-step explanation:

6 <em>pages per </em>1/5 <em>hour </em>

6 <em>x 5 = 30</em>

<em>1/5= </em><em>one whole would be five parts</em>

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8 0
2 years ago
Please please help please ASAP
Vedmedyk [2.9K]

Answer:

VT = 50√3 , PT = 50

Step-by-step explanation:

Given

PV = 100

With reference angle 60°

hypotenuse (h) = 100

perpendicular (p) = ?

Now

Sin 60° = p/h

√3 / 2 = p / 100

p = √3 * 100 / 2

p = 50√3

Also

With reference angle 30°

hypotenuse (h) = 100

perpendicular (p) = ?

sin 30° = p/h

1/2 = p / 100

p = 100 / 2

p = 50

Hope it will help :)

8 0
3 years ago
​Jessie bought 11 red roses and 7 white roses. The ratio of the number of red roses to the number of white roses is...
ankoles [38]

Answer:

11/8 and if you need percentage its about 61%

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What would the following system of equations look like in augmented matrix form?
AlladinOne [14]
[<span><span><span>​2</span><span>​5</span><span>​​</span></span><span><span>​3</span><span>​2</span><span>​​</span></span><span><span>​8</span><span>​2</span><span>​​</span></span></span><span>]</span>
3 0
3 years ago
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th
mash [69]

Answer:

The rocket hits the gorund after approximately 10.71 seconds.

Step-by-step explanation:

The height of the rocket <em>y</em> in feet <em>x</em> seconds after launch is given by the equation:

y=-16x^2+165x+69

And we want to find the time in which the rocket will hit the ground.

When it hits the ground, its height above ground will be 0. Hence, we can let <em>y</em> = 0 and solve for <em>x: </em>

<em />0=-16x^2+165x+69<em />

We can use the quadratic formula:

\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

In this case, <em>a</em> = -16, <em>b</em> = 165, and <em>c </em>= 69.

Substitute:

\displaystyle x=\frac{-165\pm\sqrt{(165)^2-4(-16)(69)}}{2(-16)}

Evaluate:

\displaystyle x=\frac{-165\pm\sqrt{31641}}{-32}=\frac{165\pm\sqrt{31641}}{32}

Hence, our solutions are:

\displaystyle x_1=\frac{165+\sqrt{31641}}{32}\approx 10.71\text{ or } x_2=\frac{165-\sqrt{31641}}{32}\approx-0.40

Since time cannot be negative, we can ignore the first answer.

So, the rocket hits the gorund after approximately 10.71 seconds.

7 0
2 years ago
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