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Murljashka [212]
4 years ago
6

Write y= -4x² -16x -14 in vertex form.

Mathematics
1 answer:
adell [148]4 years ago
5 0
  • Put brackets around the first two terms on the right. y = (-4x^2 - 16x) - 14
  • Pull out the common factor in the first two terms. y = -4(x^2 + 4x) - 14
  • Divide the middle term by 2. Add that inside the brackets. square y = -4(x^2 +4x +(4/2)^2 - 14
  • y = -4(x^2 + 4x + 4) - 14 + 16 This is the step where most people stumble. The point is why is 16 added? It is because what you have done inside the brackets is multiplied 4 by - 4 (on the left). That means you have changed the equation by -16. To counter that, you must add 16 after the - 14. The result is y= -4(x^2 + 4x+4) + 2
  • Express the terms inside the brackets as a square. y =  - 4(x + 2)^2 + 2

B and D are both wrong. B has +4 outside the brackets. It is - 4

D is wrong because there is no 4 of any kind outside the brackets.

A is incorrectly represented inside the brackets as 16. That's not right

That only leaves  C. <<<< Answer

Graphs

Notice that the red parabola and the green one are the same thing.

Red: y = -4x^2 - 16x - 14

Green: y = -4(x + 2)^2 + 2

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A culture of bacteria has an initial population of 9300 bacteria and doubles every 3
sp2606 [1]

Answer:

The approximate population of bacteria in the culture after 10 hours is 93,738.  

Step-by-step explanation:

<h3>General Concepts:</h3>
  • Exponential Functions.
  • Exponential Growth.
  • Doubling Time Model.
  • Logarithmic Form.

BPEMDAS Order of Operations:

  1. Brackets.
  2. Parenthesis.
  3. Exponents.
  4. Multiplication.
  5. Division.
  6. Addition.
  7. Subtraction.
<h2>Definitions:</h2>

We are given the following Exponential Growth Function (Doubling Time Model), \displaystyle\mathsf{P_{(t)}\:=\:P_0\cdot2^{(t/d)}} where:

  • \displaystyle\sf{P_t\:\:\rightarrow} The population of bacteria after “<em>t </em>” number of hours.
  • \displaystyle\sf{P_0 \:\:\rightarrow} The initial population of bacteria.
  • \displaystyle{t \:\:\rightarrow}  Time unit (in hours).
  • \displaystyle{\textit d \:\:\rightarrow}  Doubling time, which represents the amount of time it takes for the population of bacteria to grow exponentially to become twice its initial quantity.  
<h2>Solution:</h2>

<u>Step 1: Identify the given values.</u>

  • \displaystyle\sf{P_0\:=} 9,300.
  • <em>t</em> = 10 hours.
  • <em>d</em> = 3.  

<u>Step 2: Find value.</u>

1. Substitute the values into the given exponential function.

  \displaystyle\mathsf{P_{(t)} = P_0\cdot2^{(t/d)}}

  \displaystyle\mathsf{\longrightarrow P_{(10)} = 9300\cdot2^{(10/3)}}

2. Evaluate using the BPEMDAS order of operations.

  \displaystyle\mathsf{P_{(10)} = 9300\cdot2^{(10/3)}\quad \Longrightarrow BPEMDAS:\:(Parenthesis\:\:and\:\:Division).}

  \displaystyle\sf P_{(10)} = 9300\cdot2^{(3.333333)}\quad\Longrightarrow BPEMDAS:\:(Exponent).}

  \displaystyle\sf P_{(10)} = 9300\cdot(10.079368399)\quad \Longrightarrow BPEMDAS:(Multiplication).}

 \boxed{\displaystyle\mathsf{P_{(10)} \approx 93,738.13\:\:\:or\:\:93,738}}

Hence, the population of bacteria in the culture after 10 hours is approximately 93,738.  

<h2>Double-check:</h2>

We can solve for the amount of <u>time</u> <u>(</u><em>t</em> ) it takes for the population of bacteria to increase to 93,738.

1. Identify given:

  • \displaystyle\mathsf{P_{(t)} = 93,738 }.
  • \displaystyle\mathsf{P_0 = 9,300}.
  • <em>d </em>= 3.

2. Substitute the values into the given exponential function.

  \displaystyle\mathsf{P_{(t)} = P_0\cdot2^{(t/d)}}

  \displaystyle\mathsf{\longrightarrow 93,378 = 9,300\cdot2^{(t/3)}}

3. Divide both sides by 9,300:

  \displaystyle\mathsf{\longrightarrow \frac{93,378}{9,300} = \frac{9,300\cdot2^{(t/3)}}{9,300}}

  \displaystyle\mathsf{\longrightarrow 10.07936840 = 2^{(t/3)}}

4. Transform the right-hand side of the equation into logarithmic form.

  \boxed{\displaystyle\mathsf{\underbrace{ x = a^y}_{Exponential\:Form} \longrightarrow \underbrace{y = log_a x}_{Logarithmic\:Form}}}    

  \displaystyle\mathsf{\longrightarrow 10.07936840 = \bigg[\:\frac{t}{3}\:\bigg]log(2)}  

5. Take the <em>log</em> of both sides of the equation (without rounding off any digits).  

  \displaystyle\mathsf{log(10.07936840) = \bigg[\:\frac{t}{3}\:\bigg]log(2)}

  \displaystyle\mathsf{\longrightarrow 1.003433319 = \bigg[\:\frac{t}{3}\:\bigg]\cdot(0.301029996)}

6. Divide both sides by (0.301029996).

  \displaystyle\mathsf{\frac{1.003433319}{0.301029996} = \frac{\bigg[\:\frac{t}{3}\:\bigg]\cdot(0.301029996) }{0.301029996}}

  \displaystyle\mathsf{\longrightarrow 3.3333333  = \frac{t}{3}}

7. Multiply both sides of the equation by 3 to isolate "<em>t</em>."

  \displaystyle\mathsf{(3)\cdot(3.3333333)  = \bigg[\:\frac{t}{3}\:\bigg]\cdot(3)}

  \boxed{\displaystyle\mathsf{t\approx10}}

Hence, it will take about 10 hours for the population of bacteria to increase to 93,378.    

__________________________________

Learn more about Exponential Functions on:

brainly.com/question/18522519            

7 0
2 years ago
(8+5i) + (10+6i)-(3+6i)
Natali [406]

Answer:

15 + 5i

Step-by-step explanation:

(8+5i) + (10+6i)-(3+6i) \\  \\  = 8 + 5i + 10 + 6i - 3 - 6i \\  \\  =( 8 + 10 - 3 )+ (5i + 6i - 6i )\\  \\  = 15 + 5i

8 0
3 years ago
Find the length of the curve given by ~r(t) = 1 2 cos(t 2 )~i + 1 2 sin(t 2 ) ~j + 2 5 t 5/2 ~k between t = 0 and t = 1. Simplif
xxMikexx [17]

Answer:

The length of the curve is

L ≈ 0.59501

Step-by-step explanation:

The length of a curve on an interval a ≤ t ≤ b is given as

L = Integral from a to b of √[(x')² + (y' )² + (z')²]

Where x' = dx/dt

y' = dy/dt

z' = dz/dt

Given the function r(t) = (1/2)cos(t²)i + (1/2)sin(t²)j + (2/5)t^(5/2)

We can write

x = (1/2)cos(t²)

y = (1/2)sin(t²)

z = (2/5)t^(5/2)

x' = -tsin(t²)

y' = tcos(t²)

z' = t^(3/2)

(x')² + (y')² + (z')² = [-tsin(t²)]² + [tcos(t²)]² + [t^(3/2)]²

= t²(-sin²(t²) + cos²(t²) + 1 )

................................................

But cos²(t²) + sin²(t²) = 1

=> cos²(t²) = 1 - sin²(t²)

................................................

So, we have

(x')² + (y')² + (z')² = t²[2cos²(t²)]

√[(x')² + (y')² + (z')²] = √[2t²cos²(t²)]

= (√2)tcos(t²)

Now,

L = integral of (√2)tcos(t²) from 0 to 1

= (1/√2)sin(t²) from 0 to 1

= (1/√2)[sin(1) - sin(0)]

= (1/√2)sin(1)

≈ 0.59501

8 0
3 years ago
Erin has quarters and nickels for a total of 16 coins. The value of his coins is $2.60. Let represent the number of quarters and
Aneli [31]

Note: Consider we need to find each type of coins he has.

Given:

Erin has quarters and nickels for a total of 16 coins.

The value of his coins is $2.60.

To find:

The number of each type of coins.

Solution:

Let x represent the number of quarters and y represent the number of nickels.

According to the question,

Total coins : x+y=16        ...(i)​

Total value : 0.25x+0.05y=2.60        ...(ii)​

Multiply equation (i) by 0.25 and subtract the result from (ii).

0.25x+0.05y-0.25(x+y)=2.60-0.25(16)

0.25x+0.05y-0.25x-0.25y=2.60-4

-0.20y=-1.40

Divide both sides by -0.20.

y=7

Put y=7 in (i).

x+7=16

x=16-7

x=9

Therefore, the number of quarters is 9 and number of nickels is 7.

6 0
3 years ago
Write the ratios for sin M, cos M, and tan M.
Dominik [7]

Answer:

Sin M= opposite/hypotenuse, cos M= adjacent/Hypotenuse, tan M= opposite/adjacent

Step-by-step explanation:

7 0
2 years ago
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