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blagie [28]
3 years ago
14

If we recreated the scene from Fast & Furious 7 and dropped a Challenger SRT® Hellcat Redeye Widebody from a C-130 aircraft

at 5,280 ft, how much horsepower would it take to drive past it before it hits the ground if you’re 1 mile away?
Mathematics
2 answers:
padilas [110]3 years ago
6 0

Answer:

7

Step-by-step explanation:

MissTica3 years ago
4 0

Answer:

After calculating all this, I came up with an answer around 474.34812 which is close to one of the offered answers of 475 HP, so I selected that.

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E/2=3 please help ASAP
nordsb [41]

Answer:

E= 6

Step-by-step explanation:

6/2 = 3

hope this helped!

8 0
2 years ago
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Could someone explain to me what is the process
Phoenix [80]

Answer:

You just multiple the number of apples one truck can carry by the number of trucks total.

The second one you divide 4551 by 37 and round your answer up.

Step-by-step explanation:

So it would be 23*37.

3 0
3 years ago
Read 2 more answers
I can’t figure this out at all.
Liula [17]
The fact that this triangle is a right angle triangle makes you now have 2 angles and the 1 side given, so it should be solvable.
First, You know that A=46 and C=90 as it is the right angle, and you know that the sum of any triangle's angles is 180. so now B=180-(90-46)=44
Now to the sides,
sin(B)=opp./hyp.=b/c=8/c=sin(44)
so, c=8/sin(44) which is approximately 11.52 unit length
now, use Pythagoras to find a,
a=√c²-b² =√11.52²-8² which is approximately 8.3 unit length.
Hope this helps.

6 0
3 years ago
Find the missing factor BBB that makes the equality true.
loris [4]

Answer:21y^4= B*7y^3

B=(21y^4)/(7y^3)

B=3y

i think this is correct

4 0
3 years ago
At a local University, it is reported that 81% of students own a wireless device. If 5 students are selected at random, what is
Sphinxa [80]

Answer:

34.87% probability that all 5 have a wireless device

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they own a wireless device, or they do not. The probability of a student owning a wireless device is independent from other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

81% of students own a wireless device.

This means that p = 0.81

If 5 students are selected at random, what is the probability that all 5 have a wireless device?

This is P(X = 5) when n = 5. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{5,5}.(0.81)^{5}.(0.19)^{0} = 0.3487

34.87% probability that all 5 have a wireless device

5 0
3 years ago
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