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Delvig [45]
2 years ago
9

A triangle contains angles mesuring 28 degrees and 37 degrees. How many degrees is the third angle?​

Mathematics
1 answer:
Orlov [11]2 years ago
8 0

Answer:

  • 115°

Step-by-step explanation:

<u>We know that:</u>

  • Angles ∠A and ∠B are 28° and 37°.

<u>We don't know:</u>

  • Angle ∠C's angle

<u>So, we do this:</u>

  • Add the 180°
  • Solve the equation 180 - 28 - 37

<u>Solve:</u>

  • 180 - 28
  • = 152 - 37
  • = 115.

Angle ∠C is 115°.

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Given: Z = 0.43Y + 12 ; What is Y when Z = 28
jolli1 [7]
Z = 0.43Y + 12; Z = 28
28 = 0.43Y + 12; insert value of Z
16 = 0.43Y; subtract 12 from both sides
37.21 = Y; divide both sides by 0.43; rounded to nearest hundredth
5 0
3 years ago
The cost of unleaded gasoline in the Bay Area once followed an unknown distribution with a mean of $4.09 and a standard deviatio
WINSTONCH [101]

Answer:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\mu_{\bar X} = 4.09

\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}= \frac{0.08}{\sqrt{16}}= 0.02

So the best answer for this case would be:

\bar X \sim N (4.09,  \frac{0.08}{\sqrt{16}}= 0.02)

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the costs of unleaded gasoline of a population, and for this case we know the distribution for X is given by:

X \sim N(4.09,0.08)  

Where \mu=4.09 and \sigma=0.08

We select a sample size of n =16. Since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\mu_{\bar X} = 4.09

\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}= \frac{0.08}{\sqrt{16}}= 0.02

So the best answer for this case would be:

\bar X \sim N (4.09,  \frac{0.08}{\sqrt{16}}= 0.02)

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Simora [160]
The total cost of the least expensive fence would be $800.

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