Put these numbers in order from least to greatest.<br> 0.6<br> 11<br> -0.1<br> 11 3/15

boyakko [2]

Bob the numerator and denominator are divisible by 3 so the simplified fraction would be 9/17

8 0

3 years ago

Of a group of randomly selected adults, 360 identified themselves as manual laborers, 280 identified themselves as non-manual wa

Wittaler [7]

Answer:

We are 95% confident that the percent of executives who prefer trucks is between 19.43% and 33.06%

Step-by-step explanation:

We are given that in a group of randomly selected adults, 160 identified themselves as executives.

n = 160

Also we are given that 42 of executives preferred trucks.

So the proportion of executives who prefer trucks is given by

p = 42/160

p = 0.2625

We are asked to find the 95% confidence interval for the percent of executives who prefer trucks.

We can use normal distribution for this problem if the following conditions are satisfied.

n×p ≥ 10

160×0.2625 ≥ 10

42 ≥ 10 (satisfied)

n×(1 - p) ≥ 10

160×(1 - 0.2625) ≥ 10

118 ≥ 10 (satisfied)

The required confidence interval is given by

$p \pm z\times \sqrt{\frac{p(1-p)}{n} }$

Where p is the proportion of executives who prefer trucks, n is the number of executives and z is the z-score corresponding to the confidence level of 95%.

Form the z-table, the z-score corresponding to the confidence level of 95% is 1.96

$p \pm z\times \sqrt{\frac{p(1-p)}{n} }$

$0.2625 \pm 1.96\times \sqrt{\frac{0.2625(1-0.2625)}{160} }$

$0.2625 \pm 1.96\times 0.03478$

$0.2625 \pm 0.06816$

$0.2625 - 0.06816, \: 0.2625 + 0.06816$

$(0.1943, \: 0.3306)$

$(19.43\%, \: 33.06\%)$

Therefore, we are 95% confident that the percent of executives who prefer trucks is between 19.43% and 33.06%

5 0

3 years ago

If a Customer places an order for $47.36 and it’s late, then how much would the customer be refunded if the refund is 20% on the

Serggg [28]

$9.47

I just multiplied the total by the refund percentage to get that number. It’s just like finding a tip.

6 0

2 years ago

Paul bought a student discount card for the bus. The card allows him to buy daily bus passes for $1.60. After one month, Paul bo

Annette [7]

Paul spent $6 on the student discount card. 23 times 1.60 equals 36.80. Subtract that from 42.80 and you get 6

6 0

3 years ago

Please help on these two

jeyben [28]

Answer:

For your first problem you want to see what all the sides would equal

You would have to combine them all into one big equation

5x-7+3x+1+4x=30 (now you want to combine like terms)

12x-7+1=30 (combined the x's together)

12x-6=30 (added -7 and 1)

12x=36 (added 6 to each side)

x=3 (divided 12 to each side)

Now you wanna plug 4 in for x for each side to find out the largest to smallest

AB=5(3)-7= 8

BC=3(3)+1= 10

AC=4(3)= 12

So in order from smallest to largest would be angle C, B, A because

Angle C is the smallest angle because the sides AC and BC are the longest so they form the smallest angle

Then it would be angle A being the largest because the smallest sides in length AB and BC make up the biggest angle

The next problem would be that in order for it to have to be a triangle the two smallest sides needs to add up higher than the third side so

11, 11, 24, 11+11=22, which is less than 24 so not this one

18,12,9, 9+12=21 which is greater that 18 so this one would be a triangle

9,10,19, 9+10=19 which 19 isn't greater than 19 so this one is not a triangle

4,7,23, 4+7=11 which is less than 23, so this one is also not a triangle

So your answer would be 18cm,12cm,9cm

8 0

3 years ago

Put these numbers in order from least to greatest. 0.6 11 -0.1 11 3/15