The answer to your question is 21.
7 * 3 = 21
The answer is (4, -6), or the fourth option.
It's not clear whether you meant 30n^(2b) or [30n^2] b.
I will assume the latter.
b can then be factored out of all three terms, resulting in
b [30n^2 - 87n + 30] = b [ 3 ] [10n^2 - 29n + 10 ]
Can you factor this further?
Answer:
The observation would be considered unusual because it is farther than three standard deviations from the mean.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
When Z has an absolute value higher than 2, the observation is considered unusual.
In this problem, we have that:




So the correct answer is:
The observation would be considered unusual because it is farther than three standard deviations from the mean.
The answer is 2.
Hope this helped!!!