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3 years ago

Triangle ABC has angle measures as shown A x-5 B 3x+30 C 35 qhat is the value x

Mathematics

2 answers:

Allushta [10]3 years ago

6 0

Answer:

The value of x = 30

Step-by-step explanation:

It is given that,

In triangle ABC,

<A = x - 5, <B = 3x + 30 and <C = 35

To find the value of x

<A + <B + <C = 180 [ angle sum property]

(x - 5 ) + (3x + 30 ) + 35 = 180

x - 5 + 3x + 30 + 35 = 180

x + 3x - 5 + 30 + 35 = 180

4x + 60 = 180

4x = 180 - 60

4x = 120

x = 120/4 = 30

Therefore the value of x = 30

To find <A and <B

<A = x - 5

<A = 30 - 5 = 25°

<B = 3x + 30

<B = 3*30 + 30 = 90 + 30 = 120°

Vinvika [58]3 years ago

5 0

Answer:

$x=30\ degrees$

$m$

Step-by-step explanation:

we know that

The sum of interior angles in a triangle must be equal to 180 degrees

$(x-5)+(3x+30)+(35)=180\°$

solve for x

$4x=180\°-60\°$

$4x=120\°$

$x=30\°$

$m$

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Answer:

95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is [0.265 , 0.316].

Step-by-step explanation:

We are given that in a simple random sample of 1219 US adults, 354 said that their favorite sport to watch is football.

Firstly, the pivotal quantity for 95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = proportion of adults in the United States whose favorite sport to watch is football in a sample of 1219 adults = $\frac{354}{1219}$

n = sample of US adults = 1291

p = population proportion of adults

Here for constructing 95% confidence interval we have used One-sample z proportion statistics.

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5%

significance level are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ ) = 0.95

95% confidence interval for p = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ ]

= [ $\frac{354}{1219}-1.96 \times {\sqrt{\frac{\frac{354}{1219}(1-\frac{354}{1219})}{1219} }$ , $\frac{354}{1219}+1.96 \times {\sqrt{\frac{\frac{354}{1219}(1-\frac{354}{1219})}{1219} }$ ]

= [0.265 , 0.316]

Therefore, 95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is [0.265 , 0.316].

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