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klemol [59]
3 years ago
8

Let f be the function given by the sum of the first three nonzero terms of this series. The maximum value of |lnx-f(x)| for .3&l

t;=x<=1.7 is:__________
Mathematics
1 answer:
kodGreya [7K]3 years ago
4 0

Answer:

Step-by-step explanation:

f(x) = sin(4x)f'    = 4 cos(4x)f''   = -16 sin(4x)f'''  = -64 cos(4x)f⁽⁴⁾ = 256 sin(4x)f⁽⁵⁾ = 1024 cos(4x)The 4-th order Taylor series expansion isf(x+h) = f(x) + hf'(x) + (h²/2!)f''(x) + (h³/3!)f'''(x) + (h⁴/4!)f⁽⁴⁾(x) + ...The Maclaurin series is obtained by setting x = 0.Note that sin(0) = 0 and cos(0) = 1.The non zero terms aref(h) = 4h - (4h)³/3! + (4h)⁵/5! - (4h)⁷/7! + ...Answer: f(x) =4x- 4/3+4x/5+4x7

HOPE THIS HELPED ;3 please mark Brainliest

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Bus A and Bus B leave the bus depot at 8 am.
LenaWriter [7]

Answer: 10:55

Step-by-step explanation:

Taking statement at face value and the simplest scenario that commencing from 08:00am the buses take a route from depot that returns bus A to depot at 25min intervals while Bus B returns at 35min intervals.

The time the buses will be back at the depot simultaneously will be when:

N(a) * 25mins = N(b) * 35mins

Therefore, when N(b) * 35 is divisible by 25 where N(a) and N(b) are integers.

Multiples of 25 (Bus A) = 25, 50, 75, 100, 125, 150, 175, 200 etc

Multiples of 35 (Bus B) = 35, 70, 105, 140, 175, 210, 245 etc

This shows that after 7 circuits by BUS A and 5 circuits by Bus B, there will be an equal number which is 175 minutes.

So both buses are next at Depot together after 175minutes (2hr 55min) on the clock that is

at 08:00 + 2:55 = 10:55

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3 years ago
The volume of
STALIN [3.7K]
100 drops =1fluid ounce 1 drop= 1/100 ounce Hence 10 drops =10/100=1/10
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How many times greater is the value of the 2 in 204,936 than the value of the 2 in 124,936
miss Akunina [59]
10 times 20,000 equals 200,000. So the answer is C, the value of the 2 is 10 times greater
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The area of a rectangle is 20 square inches. If the length is 4 inches less than 6 times the width, then find the dimensions of
Tpy6a [65]

Step-by-step explanation:

Let the width=x

Length =6x-4

As we know that in a rectangle

{\boxed{\sf Area=LB}}

  • Substitute the values

\hookrightarrow\sf x (6x-4)=20

\hookrightarrow\sf 6x^2-4x=20

\hookrightarrow\sf 6x^2-4x-20=0

  • Here a=6, b=-4, c=-20.
  • use quadratic formula

\hookrightarrow\sf x=\dfrac {1}{3}+\dfrac {1}{3}\sqrt {31} \quad or \quad \dfrac {1}{3}+\dfrac {-1}{3}\sqrt {31}

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