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mel-nik [20]
2 years ago
14

Square root y is a rational between square root 33 and square root 50 find y​

Mathematics
1 answer:
Vesnalui [34]2 years ago
4 0

The value of y are 36 and 49 since they are perfect numbers

From the question, we need to get the perfect square between 33 and 50

<h3>Perfect numbers</h3>
  • Perfect squares are numbers that can be are squares of an integer.

  • From the information given, we can see that 36 and 49 are the perfect numbers between 33 and 50.

Hence the value of y if square root y is a rational between square root  

33 and square root 50 is 36 and 49

Learn more on Perfect squares  here: brainly.com/question/1538726

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ATHLETICS of 107 athletes surveyed about what sport they play, some play basketball. of those that play basketball , 48 play bas
aliina [53]

the number of athletes who do not play basketball is 26.

Step-by-step explanation:

<u>DATA:</u>

Athletes surveyed = 107 athletes

<u>Athletes who play basketball</u>

Athletes who play baseball = 48 athletes

Athletes who don't play baseball = 33 athletes

Athletes who play basketball = athletes who play baseball + athletes who don't play baseball

Athletes who play basketball = 48 + 33

Athletes who play basketball = 81

<u>EQUATION:</u>

Total athletes = Athletes who play basketball + Athletes who don't play basketball

107 = 81 + x

x = 107 - 81

x = 26

Therefore,  the number of athletes who do not play basketball is 26.

Keyword: equations

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#LearnwithBrainly

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3 years ago
Find x for this problem<br> 2(x-5)+6=7-3(2x-4)
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Answer:

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Step-by-step explanation:

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4 0
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A police cruiser is traveling at 20.0 m/s when the officer spies a speeder. The cruiser accelerates at 3.0 m/s^2 for 5.0 seconds
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For the first 5.0 seconds, the cruiser covers a distance of

\left(20.0\dfrac{\rm m}{\rm s}\right)(5.0\,\mathrm s)+\dfrac12\left(3.0\dfrac{\rm m}{\mathrm s^2}\right)(5.0\,\mathrm s)^2=137.5\,\mathrm m

At this point, the cruiser will have achieved a velocity of

\left(20.0\dfrac{\rm m}{\rm s}\right)+\left(3.0\dfrac{\rm m}{\mathrm s^2}\right)(5.0\,\mathrm s)=35\dfrac{\rm m}{\rm s}

The cruiser will take

\left(35\dfrac{\rm m}{\rm s}\right)-\left(5.0\dfrac{\rm m}{\mathrm s^2}\right)t=0\implies t=7.0\,\mathrm s

to come to a stop as it decelerates. It will have covered a total distance of

(137.5\,\mathrm m)+\left(35\dfrac{\rm m}{\rm s}\right)(7.0\,\mathrm s)+\dfrac12\left(-5.0\dfrac{\rm m}{\mathrm s^2}\right)(7.0\,\mathrm s)^2=\boxed{260\,\mathrm m}

8 0
3 years ago
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