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2 years ago

−7x−9 from -4x^2+3x-5−4x 2 +3x−5.

Mathematics

1 answer:

Likurg_2 [28]2 years ago

8 0

Answer:

− 4 x ^2 + 2 x − 8

Step-by-step explanation:

Subtract 4 x from 3x. (-4x^2+3x-5−4x)

= -4x^2-x-5

Subtract 5 from 2 (2 +3x−5)

= 3x-3

Put it together (-4x^2-x-5+3x-3)

Simplify the expression.

Answer = -4x^2+2x-8

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Solving a right triangle (ROUND TO THE NEAREST TENTH)

Kay [80]

Answer:

see explanation

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Subtract the sum of the given angles from 180 for B

B = 180° - (90 + 40)° = 180° - 130° = 150°

--------------------------------------------------------------

sin40° = $\frac{opposite}{hypotenuse}$ = $\frac{a}{21}$

Multiply both sides by 21

21 × sin40° = a, thus

a ≈ 13.5 ( to the nearest tenth )

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cos40° = $\frac{adjacent}{hypotenuse}$ = $\frac{b}{21}$

Multiply both sides by 21

21 × cos40° = b, thus

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3 0

3 years ago

Give 1 pair of Vertical and 1 pair of Supplementary angles

mojhsa [17]

Solution:

Vertical angles are a pair of opposite angles formed by intersecting lines. re vertical angles. Vertical angles are always congruent.

These two angles (140° and 40°) are Supplementary Angles because they add up to 180°:

Notice that together they make a straight angle.

Hence,

From the image

The following pairs form vertical angles

$\begin{gathered} \angle1=\angle3(vertical\text{ angles)} \\ \angle2=\angle4(vertical\text{ angles)} \\ \angle5=\angle7(vertical\text{ angles)} \\ \angle6=\angle6(vertical\text{ angles)} \end{gathered}$

Hence,

One pair of the vertical angles is ∠1 and ∠3

Part B:

Two angles are said to be supplementary when they ad together to give 180°

Hence,

From the image,

The following pairs are supplementary angles

$\begin{gathered} \angle5+\angle6=180^0(supplementary\text{ angles)} \\ \angle5+\angle8=180^0(supplementary\text{ angles)} \\ \angle7+\angle8=180^0(supplementary\text{ angles)} \\ \angle6+\angle7=180^0(supplementary\text{ angles)} \\ \angle1+\angle2=180^0(supplementary\text{ angles)} \\ \angle1+\angle4=180^0(supplementary\text{ angles)} \\ \angle2+\angle3=180^0(supplementary\text{ angles)} \\ \angle3+\angle4=180^0(supplementary\text{ angles)} \end{gathered}$

Hence,

One pair of supplementary angles is ∠5 and ∠6

8 0

10 months ago

Evaluate sigma 12 n=3-5n-1

Leni [432]

12n = 3-5n-1 or n =3-5n-1???