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sergiy2304 [10]
3 years ago
8

Please help me i dont understand this

Mathematics
2 answers:
DiKsa [7]3 years ago
5 0
You have to find slope which is Y=MX+B so it would be m as slope so u then solve
Amanda [17]3 years ago
3 0
If you put that on a graph with the bottom left point at (0,0), the top point of the triangle would be at (10,6), so for every 6 it rises, it runs 10. the slope is 6/10, simplified to 3/5
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PLS HELP ASAP. Thank you! <br><br><br> Will mark brainliest.
AlekseyPX

Answer:

Volume: 2047.5 in. cubes

surface area: 1067.5 in.

3 0
2 years ago
(x + y + 3)(x + y - 4) multiplying polynomials
Yuliya22 [10]
X^2 + 2xy + -x + y^2 + -y + -12
4 0
3 years ago
Are the side lengths congruent?
Serhud [2]

Answer:

The side lengths are not congruent. Evidence: Becuase the line shows that one is higher. None of the sides are parallel. Evidence: none of the lines of the shape are on the exact same line. No the adjacent sides are not perpendicular. Evidence: They are crooked and you can tell becuase of how the shape is on the line. The most specific shape is a rhombus. A rhombus is a crooked square. This isn't a perfect rhombus.

Step-by-step explanation:

5 0
2 years ago
Can you please explain to me what the end behavior of the function f(x)=-2x^4-x^3+3 looks like?
Artist 52 [7]
The dominant term is -2x⁴. 

As X approaches infinite, y is naturally going to be really large as well.

Remember that a number with an even exponent, regardless of whether it's positive or negative, will be positive.
As x approaches infinite, y will approach -2 * ∞, or -∞. Therefore, the end behavior in the positive direction is y=-∞
As x approaches negative infinite, y will approach -2 *∞ again. This is because         -∞⁴ = ∞. Therefore, the end behavior in the negative direction is also y=-∞

Basically, due to the dominance of the -2x^4 term, the function will look more or less like a downward facing parabola with a y-intercept of 3.
7 0
3 years ago
Verify a(b-c)=ab-ac for a=1.6;b=1/-2;&amp; c=-5/-7​
harina [27]

Given:

a=1.6,b=\dfrac{1}{-2},c=\dfrac{-5}{-7}

To verify:

a(b-c)=ab-ac for the given values.

Solution:

We have,

a=1.6,b=\dfrac{1}{-2},c=\dfrac{-5}{-7}

We need to verify a(b-c)=ab-ac.

Taking left hand side, we get

a(b-c)=1.6\left(\dfrac{1}{-2}-\dfrac{-5}{-7}\right)

a(b-c)=1.6\left(-\dfrac{1}{2}-\dfrac{5}{7}\right)

Taking LCM, we get

a(b-c)=1.6\left(\dfrac{-7-10}{14}\right)

a(b-c)=\dfrac{16}{10}\left(\dfrac{-17}{14}\right)

a(b-c)=\dfrac{8}{5}\left(\dfrac{-17}{14}\right)

a(b-c)=-\dfrac{68}{35}\right)

Taking right hand side, we get

ab-ac=1.6\times \dfrac{1}{-2}-1.6\times \dfrac{-5}{-7}

ab-ac=-\dfrac{16}{20}-\dfrac{8}{7}

ab-ac=-\dfrac{4}{5}-\dfrac{8}{7}

Taking LCM, we get

ab-ac=\dfrac{-28-40}{35}

ab-ac=\dfrac{-68}{35}

Now,

LHS=RHS

Hence proved.

7 0
2 years ago
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