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3 years ago

Simplify 4 square root of 2 end root plus 7 square root of 2 end root minus 3 square root of 2

Mathematics

2 answers:

ehidna [41]3 years ago

6 0

Answer:

8√2

Step-by-step explanation:

4√2 + 7√2 - 3√2 = (√2)(4 + 7 - 3) = 8√2

Recognize that √2 is a common factor and simply add its coefficients.

mixer [17]3 years ago

3 0

$4\sqrt2+7\sqrt2-3\sqrt2=(4+7-3)\sqrt2=\boxed{8\sqrt2}\\\\Answer:\ \boxed{\text{8\ square root of 2}}$

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Please help ASAP!!!! What is the length of BC?

MatroZZZ [7]

Answer:

x=24

Step-by-step explanation:

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3 years ago

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PLEASE HELP ME EASYYYYYY MATH QUESTION BRAINLIEST

Burka [1]

Answer:

8% is equivalent to the fraction 8/100

Step-by-step explanation:

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3 years ago

A frequency table of grades has five classes (A, B, C, D,F) with frequencies of 4, 10, 17, 6, and respectively. Using percentage

fiasKO [112]

We have the frequencies for each of the grades. We can estimate the number of students graded by adding all those frequencies. Let's call N the total number of grades:

$\begin{gathered} N=4+10+17+6+2 \\ N=39 \end{gathered}$

We have then a total number of grades of 39.

The corresponding relative frequency for a grade is the ratio of the frequency to the total number of "samples", 39 in this case.

Then, for grade A, the relative frequency (RF) will be:

$RF_A=\frac{4}{39}\approx0.10256\approx10.26\text{ \%}$

This will be the fraction of the total grades that are A. Represented as a percentage will be 10.26%, rounded to two decimal places.

Now, to complete the table we do the same for the other frequencies:

For grade B:

$RF_B=\frac{10}{39}\approx0.2564\approx25.64\text{ \%}$

For grade C:

$RF_C=\frac{17}{39}\approx0.4359\approx43.59\text{ \%}$

For grade D:

$RF_D=\frac{6}{39}\approx0.1538\approx15.38\text{ \%}$

For grade F:

$RF_D=\frac{2}{39}\approx0.0513\approx5.13\text{ \%}$

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1 year ago

Bethany and Aidan each have candy bars that are the same size and shape. Bethany's candy bar is marked so that it can be broken

vivado [14]

Answer:

Step-by-step explanation:

This problem is most likely about what percentage of the candy does each individual have left. Since the phrase is explaining that each ones candy bar is the same size and can be broken into equally divided pieces then it is most likely about figuring out which one of the individual's has more candy left over when compared to the other's candy. This is possible since both candies are the same size but more information would be needed.

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3 years ago

The American Management Association is studying the income of store managers in the retail industry. A random sample of 49 manag

VashaNatasha [74]

Answer:

a) The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.

b) The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.

Step-by-step explanation:

Question a:

We have to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.95}{2} = 0.025$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a p-value of $1 - 0.025 = 0.975$ , so Z = 1.96.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.96\frac{2050}{\sqrt{49}} = 574$

The lower end of the interval is the sample mean subtracted by M. So it is 45420 - 574 = $44,846.

The upper end of the interval is the sample mean added to M. So it is 45420 + 574 = $45,994.

The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.

Question b:

The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.

5 0

3 years ago