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3 years ago

PLEASE HELP IM DYING AND DUMB

Mathematics

2 answers:

valkas [14]3 years ago

6 0

Answer:

11√7 / 7

Step-by-step explanation:

11 / √7 = (11 * √7 ) / (√7 x √7) = 11√7 / 7

il63 [147K]3 years ago

5 0

2nd one is the answer

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Which of the following transformations preserves orientation, but does NOT preserve congruence?

AlexFokin [52]

Reflection does not preserve orientation.
Dilation (scaling), rotation and translation (shift) do preserve it.

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3 years ago

Verify the identitiy:

Advocard [28]

Answer:

$\frac{sinx}{1-cos x}$ = $cosecx$ + $cot x$

Step-by-step explanation:

To verify the identity:

sinx/1-cosx = cscx + cotx

we will follow the steps below;

We will take just the left-hand side and work it out to see if it is equal to the right-hand side

sinx/1-cosx

Multiply the numerator and denominator by 1 + cosx

That is;

$\frac{sinx}{1-cos x}$ = $\frac{sinx(1+cosx)}{(1-cosx)(1+cosx)}$

open the parenthesis on the right-hand side of the equation at the numerator and the denominator

sinx(1+cosx) = sinx + sinx cosx

(1-cosx)(1+cosx) = 1 - cos²x

Hence

$\frac{sinx(1+cosx)}{(1-cosx)(1+cosx)}$ = $\frac{sinx + sinx cosx}{1-cos^{2}x }$

But 1- cos²x = sin²x

Hence we will replace 1- cos²x by sin²x

$\frac{sinx}{1-cos x}$ = $\frac{sinx(1+cosx)}{(1-cosx)(1+cosx)}$ = $\frac{sinx + sinx cosx}{1-cos^{2}x }$ = $\frac{sinx+sinxcosx}{sin^{2}x }$

= $\frac{sinx}{sin^{2}x }$ + $\frac{sinxcosx}{sin^{2}x }$

= $\frac{1}{sinx}$ + $\frac{cosx}{sinx}$

= $cosecx$ + $cot x$

$\frac{sinx}{1-cos x}$ = $cosecx$ + $cot x$

Note that;

$\frac{1}{sinx}$ = $cosecx$

$\frac{cosx}{sinx}$ = $cot x$

6 0

3 years ago

A bakery offers a sale price of $3.50 for 4 muffins. What is the price per dozen?

Elena-2011 [213]

A dozen is 12 and since 4 is a multiple of 12, I did 12 divided by 4 which is three. So i did 3.50 multiplied by 3 and the answer is 10.50

5 0

2 years ago

Extreme cold and hot temperatures are known to affect the operation of electronic components. Winter is approaching and you are

Musya8 [376]

Answer:

A 95% confidence interval for the true mean minimum temperature that will damage an iPod is between 2.55°F and 7.45°F

Test statistic(Z) = 2.31

P-value = 0.0104

Step-by-step explanation:

Step 1

Null hypothesis: The average damaging temperature of nine iPods is 5°F

Alternate hypothesis: The average damaging temperature of nine iPods differs from 5°F

Step 2

Mean=5°F, Sd=3, df=n-1=9-1=8

The t-value corresponding to 8 degrees of freedom and 95% confidence level (5% significance level) is 2.306

Confidence Interval(CI) = (mean + or - t×sd/√n)

CI = (5 + 2.306×3/√8) = 5 + 6.918/2.828= 5+2.45=7.45°F

CI = (5 - 2.306×3/√8) = 5-2.45 = 2.55°F

Z = (sample mean - population mean)/(sd÷√n) = (5-2.55)/(3÷√8) = 2.45/1.061 = 2.31

Step 3

Using the standard distribution table, the cumulative area to the left of Z = 2.31 is 0.9896

P-value = 1 - 0.9896 = 0.0104

Step 4

Conclusion: A 95% confidence interval for the true mean minimum temperature that will damage an iPod is between 2.55°F and 7.45°F

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3 years ago

Joanie wrote a letter that was 1 1/4 pages long. Katie wrote a letter that was 3/4 page shorter than Joanie's letter. How long w

gladu [14]

The answer to your question is 2/4 which is 1/2

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3 years ago