Answer:
The series is absolutely convergent.
Step-by-step explanation:
By ratio test, we find the limit as n approaches infinity of
|[a_(n+1)]/a_n|
a_n = (-1)^(n - 1).(3^n)/(2^n.n^3)
a_(n+1) = (-1)^n.3^(n+1)/(2^(n+1).(n+1)^3)
[a_(n+1)]/a_n = [(-1)^n.3^(n+1)/(2^(n+1).(n+1)^3)] × [(2^n.n^3)/(-1)^(n - 1).(3^n)]
= |-3n³/2(n+1)³|
= 3n³/2(n+1)³
= (3/2)[1/(1 + 1/n)³]
Now, we take the limit of (3/2)[1/(1 + 1/n)³] as n approaches infinity
= (3/2)limit of [1/(1 + 1/n)³] as n approaches infinity
= 3/2 × 1
= 3/2
The series is therefore, absolutely convergent, and the limit is 3/2
Answer:
The required probability is 0.031918.
Step-by-step explanation:
Consider the provided information.
It is given that According to an article in The Wall Street Journal, this theory held for 22 out of the last 34 years.
Therefore n=34
The probability it is either up or down is 0.5.
Thus the value of p =0.5 and q = 0.5
Now calculate the probability
Let X is the number of years that theory held.
X has a binomial distribution with n=34 and p=0.5
Hence, the required probability is 0.031918.
The answer is SAS
good luck
200$ because that’s the percent
9000 if you don't allow numbers with leading zeros, such as 0,000.
10,000 if you do allow numbers with leading zeros.
