The compounds in the reaction that shifts the equilibrium with the common ion effect are 
.
<h3>What is the common ion effect?</h3>
The equilibrium condition has an equal amount of reactant and products in the reaction.
The addition of ions same as product or reactant results in a change in the equilibrium of condition and shifts the equilibrium in opposite direction.
The given reaction is:
The addition of sulfate and hydrogen ions shifts the equilibrium.
Thus, the compounds that shift the equilibrium for the reaction are .
Learn more about equilibrium, here:
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The correct answer to that question is
= 8.02
Answer:
These systems are defined both by the types of energy and matter they contain and by how that matter and energy move through and between systems. In natural systems, both energy and matter are conserved within a system. This means that energy and matter can change forms but cannot be created or destroyed.
Explanation:
You need to use the Ka for the acetic acid and the equilibrium equation.
Ka = 1.85 * 10^ -5
Equilibrium reaction: CH3COOH (aq) ---> CH3COO(-) + H(+)
Ka = [CH3COO-][H+] / [CH3COOH]
Molar concentrations at equilibrium
CH3COOH CH3COO- H+
0.50 - x x x
Ka = x*x / (0.50 - x) = x^2 / (0.50 - x)
Given that Ka is << 1 => 0.50 >> x and 0.50 - x ≈ 0.50
=> Ka ≈ x^2 / 0.50
=> x^2 ≈ 0.50 * Ka = 0.50 * 1.85 * 10^ -5 = 0.925 * 10^ - 5 = 9.25 * 10 ^ - 6
=> x = √ [9.25 * 10^ -6] = 3.04 * 10^ -3 ≈ 0.0030
pH = - log [H+] = - log (x) = - log (0.0030) = 2.5
Answer: 2.5
