Answer:
The answer to your question is:
a) 80 g of O2
b) O2, 15.13 g of CO2
c) It's not posible to know which is the limiting reactant.
Explanation:
Reaction CH4 + 2O2 ⇒ CO2 + 2H2O
a. Calculate the grams of O2 needed to react with 20.00 grams of CH4. _____________
MW CH4 = 16 g
MW O2 = 32 g
16 g of CH4 ---------------- 2(32) g of O2
20 g -------------- x
x = (20 x 64) / 16 = 80 g of O2
b. Given 15.00 g. of CH4 and 22.00 g. of O2, identify the limiting reactant and calculate the grams of CO2 that can be produced. LR _________ grams CO2 _________
.
CH4 + 2O2 ⇒ CO2 + 2H2O
15 g 22 g
16 g of CH4 ---------------- 64 g of O2
15 g of CH4 --------------- x
x = (15 x 64) / 16 = 60 g of O2
The Limiting reactant is O2 because it is necessary 60g of O2 for 16 g of CH4 and there are only 22.
CH4 + 2O2 ⇒ CO2 + 2H2O
64 g of O2 ------------------ 44 g of CO2
22 g of O2 ------------------ x
x = (22 x 44)/ 64 = 15. 13 g of CO2
c. For the reaction CH4 + 2O2 = CO2 + 2H2O, if you have 10.31 g. of CH4 and an unknown amount of oxygen, and form 20.00 g. of CO2, i. Identify if there is a limiting reactant ______________ ii. Calculate the number of grams of the limiting reactant present if there is one. ______________
CH4 + 2O2 ⇒ CO2 + 2H2O
10.31 g 20 g
We can identify the limiting reactant if we know the quantity of the reactants, if we only know the quantity of one it is not posible to which is the limiting reactant.
= 71.2 g