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3 years ago

What phase change occurs during evaporation?

Chemistry

2 answers:

vlabodo [156]3 years ago

5 0

It turns liquid to gas. Hoped this helped!!

kifflom [539]3 years ago

5 0

Liquid to gas.
Think of it like water: a puddle will eventually decrease in size and evaporate over time because its molecules gain energy and escape into the gas phase
Hope this helps!

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Please help on this one?

Bezzdna [24]

Answer:

$\text{C. } _{36}^{85}\text{Kr}$

Explanation:

Your nuclear equation is

$_{35}^{85}\text{Br} \longrightarrow \, _{-1}^{0}\text{e} +\, _{x}^{y}\text{X}$

The main point to remember in balancing nuclear equations is that

the sum of the superscripts and must be the same on each side of the equation.
the sum of the subscripts must be the same on each side of the equation.

Then

85 = 0 + y, so y = 85 - 0 = 0

35 = -1 + x, so x = 35 + 1 = 36

The nucleus with atomic number 36 and atomic mass 85 is krypton-85.

The nuclear equation becomes

$_{35}^{85}\text{Br} \longrightarrow \, _{-1}^{0}\text{e} + \, _{36}^{85}\text{Kr}$

4 0

3 years ago

Read 2 more answers

A 1.2 kg block of iron at 32 ∘C is rapidly heated by a torch such that 12 kJ is transferred to it. What temperature would the bl

lbvjy [14]

Answer:

For iron

Final temperature = 54,22°C

For copper

Final Temperature = 63.67 °C

Explanation

Hello,

You are using a torch to warm up a block of iron that has an initial temperature of 32°C.

The first you have to know is that the "heat capacity" could simply define as the heat required to go from an initial temperature to a final temperature.

So you need to use the heat capacity equation as follow in the paper.

The equation has to have all terms in the same units, so:

q = 12000 J

s = 0.450 J / g °C

m = 1200 g

Ti = 32 °C

Download odt

3 0

3 years ago

One of the reactions that occurs in a blast furnace, in which iron ore is converted to cast iron, is Fe2O3 + 3CO → 2Fe + 3CO2 Su

solong [7]

Answer:

$89.55~\%~of~Fe_2O_3~in~the~sample$

Explanation:

The first step in this reaction is the converstion from Kg of $Fe$ to grams of $Fe_2O_3$ .

$1.19x10^3~Kg~Fe~\frac{1000g~Fe}{1~Kg~Fe}~\frac{1~mol~Fe}{55.84~g~Fe}~\frac{1~mol~Fe_2O_3}{2~mol~Fe}~\frac{159.68~g~Fe_2O_3}{1~mol~Fe_2O_3}~\frac{1~Kg~Fe_2O_3}{1000~g~Fe_2O_3}$

$X~=~1.7x10^3~Kg~Fe_2O_3$

Then we can calculate the percentage of $Fe_2O_3$ in the sample:

$\%~Fe_2O_3~=~\frac{1.7x10^3~Kg~Fe_2O_3}{1.9x10^3~Kg~Sample}*100$

$89.55~\%~of~Fe_2O_3~in~the~sample$

3 0

3 years ago

The pressure of a gas in a sealed container is 152 mm hg. This translates to?

Mashcka [7]

the answer is 0.2 ATM

5 0

3 years ago

When 24g of magnesium metal is heated in air, 40g of magnesium oxide is produced. What mass of magnesium would be needed in orde

inysia [295]

Answer: 6.1 g

Explanation:

between Mg and MgO theres a 1;1 MOLE RATIO

here's the balanced equation

2Mg + O2 ==> 2MgO

24g of magnesium is approximately 1 mole of magnesium so it produces 40 g of mgo which is also 1 mole of mgo thus 10/40 =0.25 moles of MgO so 0.25 moles of magnesium would be needed which is approximately 6.1 g

6 0

3 years ago