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2 years ago

What is the value of tan(theta)?

Mathematics

1 answer:

Elodia [21]2 years ago

8 0

Answer:The tangent function is negative in the second and fourth quadrants. To find the second solution, subtract the reference angle from

to find the solution in the third quadrant.

Step-by-step explanation:

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How do you redraw a scale drawing with a new scale

rjkz [21]

Take measurements of what you want to draw, (e.g. a simple cube that is 100 cm x 100 cm x 100 cm.)
A full scale drawing would require you to draw the cube on a paper 100 cm x 100 cm x 100 cm.
If you want to 'scale', you would then redraw using new measurements. So, a 1/10 scale drawing would mean that you would redraw the cube on paper as 10 cm x 10 cm x 10 cm.
A 1/20 scale would be 5 cm x 5 cm x 5 cm. The same concept holds for all scale drawings.

3 0

2 years ago

Please help, and show me how you got the answer because i have to show for the answer thank you ❤️

snow_lady [41]

I tried my best for this I’m pretty for sure I remember doing this in school but I’m not for sure I hope this helped a little bit

6 0

2 years ago

6.Suppose the Gallup Organization wants to estimate the population proportion of those who think there should be a law that woul

drek231 [11]

Answer:

A sample of $n = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2$ is needed, in which E is the desired margin of error, as a proportion. If we find a decimal value, we round up to the next whole number.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In a previous study of 1012 randomly chosen respondents, 374 said that there should be such a law.

This means that $n = 1012, \pi = \frac{374}{1012} = 0.3696$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

How large a sample size is needed to be 95% confident with a margin of error of E?

A sample size of n is needed, and n is found when M = E.

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$E = 1.96\sqrt{\frac{0.3696*0.6304}{n}}$

$E\sqrt{n} = 1.96\sqrt{0.3696*0.6304}$

$\sqrt{n} = \frac{1.96\sqrt{0.3696*0.6304}}{E}$

$(\sqrt{n})^2 = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2$

$n = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2$

A sample of $n = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2$ is needed, in which E is the desired margin of error, as a proportion. If we find a decimal value, we round up to the next whole number.

4 0

2 years ago

a contractor needs to purchase 500 bricks. the dimensions of each brick are 5.1 cm by 10.2 by 20.3 cm, and the density of each b

AveGali [126]

No, the trailer cannot hold the weight of the bricks. It is beyond the 900kg capacity of the trailer. The total weight of the bricks is 1,013.77 kilograms. The total weight was derived from getting the volume of the brick (0.051m x 0.102m x 0.203m), then multiplying the volume to the density of each brick (1.056 x 10^3m^3 x 1920kg/m^3). The weight of each brick is 2.03kg. Lastly, multiply the total number of bricks to the weight of each brick to get the total weight.

5 0

3 years ago

X and Y are independent random variables. X is normally distributed with mean 1 and variance 1. Y is normally distributed with m

g100num [7]

Answer:

Step-by-step explanation:

Equation of variance:

Total Variance = sum (i=1, N) {c^2,variance^2}

= c1^2*variance1^2 + c2^2*variance2^2 + .....

Variance of X = 1

Variance of Y = 5

Variance of Y - 2X = (1^2)*(5) - (2^2)**(1)

= 5 - 4 = 1

8 0

2 years ago