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cluponka [151]
2 years ago
8

20 POINTS PLEASEEEE Jessica is bisecting a segment. First, she places the compass on one endpoint and opens it to a width larger

than half of the segment. What is her next step?
Swing an arc on either side of the segment.
Create a point that is not on the segment.
Draw a ray from one endpoint of the segment.
Place the compass on a point that is not on the segment.
Mathematics
1 answer:
SVETLANKA909090 [29]2 years ago
8 0

9514 1404 393

Answer:

  (a) Swing an arc on either side of the segment.

Step-by-step explanation:

The purpose of placing the compass setting its width is to draw an arc. The next step is ...

  Swing an arc on either side of the segment

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4. Using the geometric sum formulas, evaluate each of the following sums and express your answer in Cartesian form.
nikitadnepr [17]

Answer:

\sum_{n=0}^9cos(\frac{\pi n}{2})=1

\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=0

\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})=\frac{1}{2}

Step-by-step explanation:

\sum_{n=0}^9cos(\frac{\pi n}{2})=\frac{1}{2}(\sum_{n=0}^9 (e^{\frac{i\pi n}{2}}+ e^{\frac{i\pi n}{2}}))

=\frac{1}{2}(\frac{1-e^{\frac{10i\pi}{2}}}{1-e^{\frac{i\pi}{2}}}+\frac{1-e^{-\frac{10i\pi}{2}}}{1-e^{-\frac{i\pi}{2}}})

=\frac{1}{2}(\frac{1+1}{1-i}+\frac{1+1}{1+i})=1

2nd

\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=\frac{1-e^{\frac{i2\pi N}{N}}}{1-e^{\frac{i2\pi}{N}}}

=\frac{1-1}{1-e^{\frac{i2\pi}{N}}}=0

3th

\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})==\frac{1}{2}(\sum_{n=0}^\infty ((\frac{e^{\frac{i\pi n}{2}}}{2})^n+ (\frac{e^{-\frac{i\pi n}{2}}}{2})^n))

=\frac{1}{2}(\frac{1-0}{1-i}+\frac{1-0}{1+i})=\frac{1}{2}

What we use?

We use that

e^{i\pi n}=cos(\pi n)+i sin(\pi n)

and

\sum_{n=0}^k r^k=\frac{1-r^{k+1}}{1-r}

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Answer: $9

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

-13j - 20 = -8j + 20​

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subtract 20 from each side

-20-20 = 5j +20-20

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Divide by 5

-40/5 = =5j/5

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