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cluponka [151]
3 years ago
8

20 POINTS PLEASEEEE Jessica is bisecting a segment. First, she places the compass on one endpoint and opens it to a width larger

than half of the segment. What is her next step?
Swing an arc on either side of the segment.
Create a point that is not on the segment.
Draw a ray from one endpoint of the segment.
Place the compass on a point that is not on the segment.
Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
8 0

9514 1404 393

Answer:

  (a) Swing an arc on either side of the segment.

Step-by-step explanation:

The purpose of placing the compass setting its width is to draw an arc. The next step is ...

  Swing an arc on either side of the segment

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True or false? it's not possible to build a triangle with side lengths of 3 3 and 9
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True

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Simplify y-2/3/y+1/5
liberstina [14]

Answer:

\frac{15y-10}{15y-3}

Step-by-step explanation:

First at all, we need to use a=\frac{a}{1} to convert this expression into a fraction, like:

y-\frac{2}{3} to convert into \frac{y}{1} -\frac{2}{3}.

Expand the fraction to get the least common denominator, like

\frac{3y}{3*1}-\frac{2}{3}

Write all numerators above the common denominator, like this:

\frac{3y-2}{3}

The bottom one used the same way to became simplest form, like this:

y+\frac{1}{5}

\frac{y}{1} +\frac{1}{5}

\frac{5y}{5*1}+\frac{1}{5}

\frac{5y+1}{5}

And it became like this:

\frac{3y-2}{3}/\frac{5y+1}{5}

Now, we are going to simplify this complex fraction. We can use cross- multiply method to simplify this fraction.

\frac{3y-2}{3}*\frac{5y+1}{5}

3y-2(5) and 5y-1(3)

and it will becomes like this in function form:

\frac{3y-2(5)}{5y+1(3)}

Then, we should distribute 5 through the parenthesis

\frac{15y-10}{5y+1(3)}

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7 0
3 years ago
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Answer:

The answer is below

Step-by-step explanation:

Select the quadrant in which the terminal side of the angle falls.

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-150° terminates in quadrant

390° terminates in quadrant

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The x and y axis divides the cartesian plane into four equal parts known as the four quadrants.

Angles between 0° and 90° are in the first quadrant, angles between 90° and 180° are in the second quadrant, angles between 180° and 270° are in the third quadrant while angles between 270° and 360° are in the fourth quadrant.

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b) -150° = 360 - 150 = 210°. Since 210 degrees is between 180° and 270°, hence it terminates in the third quadrant.

c) 390° = 390° - 360° = 30°.

Since 30 degrees is between 0° and 90°, hence it terminates in the first quadrant.

 

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Answer:

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