the distance between (8,0) and (1,0) is 7 units
<span>The average length of crocodiles in a swamp is 11.5 feet. if the lengths are normally distributed with a standard deviation of 1.7 feet, find the probability that a crocodile is more than 11 feet long.
solution:
To obtain P(x>11) we first need to obtain the value of the z-score:
z=(11-11.5)/1.7
thus
z=-0.2941
thus
P(x>11)=1-P(z<-0.2941)=1-0.3859=0.6141
</span>
So just find 2% of 8000 and multiply by number of years since
I=PRT
R=rate
T=time in yyears
P=principle
I=interest
8000=principle
rate=2%
time in years=2
2%=0.02
so
I=8000 times 0.02 times 2
I=320
answe ris $320
Answer:
2, 1, 3, 4, 6, 5
Step-by-step explanation:
The rate of change of function f(x) on an interval [a, b] is defined as ...
average rate of change = (f(b) -f(a))/(b -a)
For the function h(x) = 2^-x, this will be ...
arc = (h(b) -h(a))/(b -a) = (2^-b -2^-a)/(b-a) = (2^-a)(2^(a-b) -1)/(b -a)
__
1. For the interval [0, 2], the average rate of change is ...
arc = (2^-0)(2^(0-2) -1)(2 -0) = (1/4 -1)/2 = -3/8 = -0.375
1 goes in the 2nd answer blank
2-6. For the other intervals, it is convenient to let a calculator or spreadsheet compute the values. The average rates of change are shown in the attachment.
Answer:

where R is the R-value and t is the thickness in inches.
Step-by-step explanation:
We are given the following in the question:
The R-value of fiberglass insulation and f its thickness have a linear relation.
Let R be the R-value and t be the thickness. Then, the equation can be written as:

where a and b are constants.
When t = 3.5, R = 11

When t = 6, R = 19

Solving the two equation, using the elimination method, we have,

Thus, the linear relationship is given by:

where R is the R-value and t is the thickness in inches.