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erastovalidia [21]
2 years ago
7

PLEASE HELP ASAP!! LUL

Mathematics
1 answer:
yawa3891 [41]2 years ago
4 0

Answer:

Step-by-step explanation:

it should add up to 360°

360=135 + 120 + 7x-64+5x-4+3x+31+4x+15+6x-8     (seems like too much huh)

360=225+25x  ( much better just add the x terms and the constants together)

135 = 25x  ( just subtract 225 from each side of the equation)

5.4 = x  ( divide 135 by 25 )

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Which of the following values have 2 significant figures? Check all that apply.
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Answer:

i would say B/90

Step-by-step explanation:

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2 years ago
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For the given table of values for a polynomial function, where must the zeros of the function lie?
Jet001 [13]

Answer:

A. Between 3.0 and 3.5 and between 4.0 and 4.5

Step-by-step explanation:

The zeroes of a function occur whenever a value of x returns zero. To predict where the zeroes lie, determine the interval(s) where the function crosses the x-axis. This occurs when either f(x) goes from a negative value to a positive value or vice versa.

From x=3.0 and x=3.5, the y-values go from 4.0 (positive) to -0.2 (negative), respectively. Therefore, there must be a zero in this interval.

From x=4.0 and x=4.5, the y-values go from -0.8 (negative) to 0.1 (positive), respectively. Therefore, there must also be a zero in this interval.

Thus, the zeros of this function occur between 3.0 and 3.5 and between 4.0 and 4.5, leading to answer choice A.

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Step-by-step explanation:

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Parallelogram JKLM has vertices J(-1, 6), K(0, 9), L(6, −3), and M(3, −3). What is the coordinates of the image if the parallelo
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Answer: (\dfrac13,-2),\ (0,-3),\ (-2,1),\ (-1,1) .

Step-by-step explanation:

Transformation rule for dilation:

(x,y)\to(kx,ky) , where k = scale factor

Given : Scale factor = -\dfrac13

Parallelogram JKLM has vertices J(-1, 6), K(0, 9), L(6, −3), and M(3, −3)

Vertices after dilation:

(-1,6)\to(-1\times\dfrac{-1}{3},6\times\dfrac{-1}{3})=(\dfrac13,-2)

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(6,-3)\to(6\times-\dfrac13,\ -3\times-\dfrac13)=(-2,1)

(3,-3)\to (3\times-\dfrac13,\ -3\times-\dfrac13)=(-1,1)

Hence, the coordinates of the image if the parallelogram = (\dfrac13,-2),\ (0,-3),\ (-2,1),\ (-1,1) .

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