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2 answers:
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Answer:
1) (x + 3)(3x + 2)
2) x= +/-root6 - 1 by 5
Step-by-step explanation:
3x^2 + 11x + 6 = 0 (mid-term break)
using mid-term break
3x^2 + 9x + 2x + 6 = 0
factor out 3x from first pair and +2 from the second pair
3x(x + 3) + 2(x + 3)
factor out x+3
(x + 3)(3x + 2)
5x^2 + 2x = 1 (completing squares)
rearrange the equation
5x^2 + 2x - 1 = 0
divide both sides by 5 to cancel out the 5 of first term
5x^2/5 + 2x/5 - 1/5 = 0/5
x^2 + 2x/5 - 1/5 = 0
rearranging the equation to gain a+b=c form
x^2 + 2x/5 = 1/5
adding (1/5)^2 on both sides
x^2 + 2x/5 + (1/5)^2 = 1/5 + (1/5)^2
(x + 1/5)^2 = 1/5 + 1/25
(x + 1/5)^2 = 5 + 1 by 25
(x + 1/5)^2 = 6/25
taking square root on both sides
root(x + 1/5)^2 = +/- root(6/25)
x + 1/5 = +/- root6 /5
shifting 1/5 on the other side
x = +/- root6 /5 - 1/5
x = +/- root6 - 1 by 5
x = + root6 - 1 by 5 or x= - root6 - 1 by 5
<h2>INVERSE VARIATION</h2>
<em>E</em><em>Q</em><em>U</em><em>A</em><em>T</em><em>I</em><em>O</em><em>N</em><em>:</em><em> </em><em> </em><em> </em><em> </em>
<em>–</em><em>–</em><em>–</em><em>–</em><em>–</em><em>–</em><em>–</em><em>–</em>
First, find the constant of variation <em>k</em> using the formula k=xy.
<em>–</em><em>–––––––</em>
Then, find <em>y</em> if <em>x</em> is equal to four using the formula y=184/x.
<em>F</em><em>i</em><em>n</em><em>a</em><em>l</em><em> </em><em>A</em><em>n</em><em>s</em><em>w</em><em>e</em><em>r</em><em>:</em>
<h2>y = 46</h2>