Answer:
the answer is 1/-4
Step-by-step explanation:
Let's write an inequality, such as follows: x < sqrt(50) < y. Square both sides of the equation. We get x^2 < 50 < y^2. Obviously, x is between 7 and 8. Also notice, that for integers a,b, (ab)^2/b^2, equals a^2. So let's try values, like 7.1. Using the previous fact, (7.1)^2, equals (71)^2/100. So, (7.1)^2, equals 50.41. Thus, our number is between 7 and 7.1. We find, with a bit of experimentation, that the square root of 50, is 7.07.
The area of a trapezpid is 1/2h×(b1+b2)
2x+1 = x-5
-x -x
X+1 = -5
-1 -1
X = -6
2(-6) +1= y
-12+1= y
-11 = y
-11 = -12+1
-11 = -6-5
Answer:
87 in³
Step-by-step explanation:
that is the solution above
