Answer:
h = 10sin(π15t)+35
Step-by-step explanation:
The height of the blade as a function f time can be written in the following way:
h = Asin(xt) + B, where:
B represets the initial height of the blade above the ground.
A represents the amplitud of length of the blade.
x represents the period.
The initial height is 35 ft, therefore, B = 35ft.
The amplotud of lenth of the blade is 10ft, therefore A = 10.
The period is two rotations every minute, therefore the period should be 60/4 = 15. Then x = 15π
Finally the equation that can be used to model h is:
h = 10sin(π15t)+35
Answer:
0.7
Step-by-step explanation:
I divided 4 by 6
0.6666666666666...
Simplify to 0.7
Considerando las fórmulas para el perímetro y el área de un rectángulo, hay que se chega en una <u>eccuación cuadrática sin solución</u>, o sea, las medidas no son posibles y la persona estaba mintiendo.
<h3>¿Cuál es la fórmula para el perímetro y el área de un rectángulo?</h3>
Considerando que las dimensiones son l y w, hay que:
- El perímetro es: P = 2(l + w).
El <u>perímetro es de 18 m</u>, o sea:
2(l + w) = 18
l + w = 9
l = 9- w.
El <u>área es de 21 m²</u>, o sea:
lw = 21
(9- w)w = 21
-w² + 9 - 21 = 0
w² - 9w + 21 = 0
El discriminante es dado por:
D = 9² - 4 x 1 x 21 = -3.
El discriminante negativo implica que la <u>eccuación cuadrática no tiene solución</u>, o sea, las medidas no son posibles y la persona estaba mintiendo.
Puede-se aprender más a cerca de el perímetro y el área de un rectángulo en brainly.com/question/26475963
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<span>The correct answer would be option C. Similar polygons
Similar polygons are polygons wherein the corresponding angles are congruent and the corresponding sides are proportional with each other. Thus, having a pair of similar polygons would mean that its corresponding angles would always be congruent.</span>
<h3>
Answer:</h3>
(x, y) = (7, -5)
<h3>
Step-by-step explanation:</h3>
It generally works well to follow directions.
The matrix of coefficients is ...
![\left[\begin{array}{cc}2&4\\-5&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%264%5C%5C-5%263%5Cend%7Barray%7D%5Cright%5D)
Its inverse is the transpose of the cofactor matrix, divided by the determinant. That is ...
![\dfrac{1}{26}\left[\begin{array}{ccc}3&-4\\5&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B26%7D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26-4%5C%5C5%262%5Cend%7Barray%7D%5Cright%5D)
So the solution is the product of this and the vector of constants [-6, -50]. That product is ...
... x = (3·(-6) +(-4)(-50))/26 = 7
... y = (5·(-6) +2·(-50))/26 = -5
The solution using inverse matrices is ...
... (x, y) = (7, -5)