Answer:
A
Step-by-step explanation:
Given
x² - 5x - 14 = 0
Consider the factors of the constant term (- 14) which sum to give the coefficient of the x- term (- 5)
The factors are - 7 and + 2, since
- 7 × 2 = - 14 and - 7 + 2 = - 5, thus
(x - 7)(x + 2) = 0
Equate each factor to zero and solve for x
x - 7 = 0 ⇒ x = 7
x + 2 = 0 ⇒ x = - 2
A,C, and D are in quadrant 3 and C is in quadrant 1
Answer:
(Sorry I could only solve the first ten for now)
1a. 17 dl (1.7 liters)
2a. 600 mm (0.6 meters)
3a. 5,000 mg (5 grams)
4a. 6.5 dm (65 meters)
5a. 7 dal (7,000 liters)
6a. 35 g (35 grams)
7a. 10 kl (10,000 liters)
8a. .07 dm (0.7 meters)
9a. 700 cg (70 grams)
10a. 0.4 dg (40 grams)
Step-by-step explanation:
Metric System:
Kilo- (k): thousand times standard unit (divide standard 1,000)
Hecto- (h): hundred times standard unit (divide standard by 100)
Deka- (da): ten times standard unit (divide standard by 10)
Meter (m); Gram (g); Liter/Litre (l): standard unit
Deci- (d): 0.1 times (a tenth of) standard unit (multiply 10 by standard)
Centi- (c): 0.01 times (a hundredth of) standard unit (multiply 100 by standard)
Milli- (m): 0.001 times (a thousandth of) standard unit (multiply standard by 1,000)
(There are more but you don't have to worry about it for now)
Answer:
one solution, no solution, infinitely many solutions
Step-by-step explanation:
I rearranged the first equation into x=6-2y
plug that into the second equation
2(6-2y)-3y=26
12-4y-3y=26
12-7y=26
-7y=14
y=-2
Then you plug that into one of the equations
x+2(-2)=6
x-4=6
x=10
The solution to the first system is (10,-2)
the second system already has one equation as something equal to a single variable so you just plug that into the other one
4x-2(2x-4)=-6
4x -4x +8 =-6
8=-6
this is a false statement so the system of equation has no solution
Lastly I rearranged the first equation into y=2x-4 and then plug that in
6x-3(2x-4)=12
6x-6x+12=12
12=12
this statement is true so the system of equations has infinite solutions