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Murrr4er [49]
3 years ago
11

How many 3/4 pound servings are in 36 pounds of meat?

Mathematics
1 answer:
pantera1 [17]3 years ago
4 0
3/4 can be converted to .75

36/.75=48

There are 48 3/4 pound servings in 36 pounds of meat. I hope I helped :-)

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What is the arc length if Θ = 2 pi over 7 and the radius is 3 cm? A. 7 pi over 12
hodyreva [135]

Answer: Option 'C' is correct.

Step-by-step explanation:

Since we have given that

\theta=\frac{2\pi}{7} \\\\r=3\ cm

An arc is a part of total circumference of circle and length of that arc is the measurement of linear distance.

Since we know the formula for "Length of an arc " , we get

L=r\times \theta\\\\L=\frac{2\pi}{7}\times 3\\\\L=\frac{6\pi}{7}

Hence, Option 'C' is correct.


6 0
3 years ago
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Can someone help me with this question please!!!!!
lianna [129]

Answer:

a = 29

u = 12

Step-by-step explanation:

32 + 7u + 9 + 2a - 3 = 3a + 7u + 9

32 + 2a - 3 = 3a

a = 29

3(29) + 7u + 9 = 180

7u = 180 - 96

7u = 84

u = 12

6 0
2 years ago
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When an electric current passes through two resistors with resistance r1 and r2, connected in parallel, the combined resistance,
kondaur [170]

Answer:

a)

The combined resistance of a circuit consisting of two resistors in parallel is given by:

\frac{1}{R}=\frac{1}{r_1}+\frac{1}{r_2}

where

R is the combined resistance

r_1, r_2 are the two resistors

We can re-write the expression as follows:

\frac{1}{R}=\frac{r_1+r_2}{r_1r_2}

Or

R=\frac{r_1 r_2}{r_1+r_2}

In order to see if the function is increasing in r1, we calculate the derivative with respect to r1: if the derivative if > 0, then the function is increasing.

The derivative of R with respect to r1 is:

\frac{dR}{dr_1}=\frac{r_2(r_1+r_2)-1(r_1r_2)}{(r_1+r_2)^2}=\frac{r_2^2}{(r_1+r_2)^2}

We notice that the derivative is a fraction of two squared terms: therefore, both factors are positive, so the derivative is always positive, and this means that R is an increasing function of r1.

b)

To solve this part, we use again the expression for R written in part a:

R=\frac{r_1 r_2}{r_1+r_2}

We start by noticing that there is a limit on the allowed values for r1: in fact, r1 must be strictly positive,

r_1>0

So the interval of allowed values for r1 is

0

From part a), we also said that the function is increasing versus r1 over the whole domain. This means that if we consider a certain interval

a ≤ r1 ≤ b

The maximum of the function (R) will occur at the maximum value of r1 in this interval: so, at

r_1=b

6 0
3 years ago
When a person is breathing normally the amount of air in their lawns varies sinusoidally. When full Karen’s lungs hold 2.8 L of
makkiz [27]

Answer:

A(t) = 2.2\sin \frac{(t - 2)\pi }{6} + 0.6

Step-by-step explanation:

Let the function of quantity in the lung of air be A(t)

So A(t) \alpha \sin (\frac{t - \alpha }{k} )

so, A(t) = Amax sin t + b

A(t) = 2.8t⇒ max

A(t) = 0.6t ⇒ min

max value of A(t) occur when sin(t) = 1

and min value of A(t) = 0

So b = 0.6

and A(max) = 2.2

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at t = 2 sec volume of a is 0.6

So function reduce to

A(t) = 2.2\sin \frac{(t - 2)}{k} + 0.6

and t = 5 max value of volume is represent

so,

\sin \frac{t - \alpha }{k} = 1

\frac{t - 2}{k} = \frac{\pi }{2} when t = 5

\frac{6}{\pi } = k

so the equation becomes

A(t) = 2.2\sin \frac{(t - 2)\pi }{6} + 0.6

7 0
3 years ago
From this diagram, select the
AURORKA [14]

O is parallel to q

let's take the angle opposite to angle 4 is alpha

angle 4 = angle alpha ( vertically opposite angles)

angle alpha = angle 3 ( as angle 4 = angle 3).

hence o is parallel to q as both the angles are equal

5 0
2 years ago
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